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iren [92.7K]
3 years ago
13

It’s a game called scattergories where you have a category and you have a letter and you have to write a valid word that matches

the catagory and starts with that same letter.
SAT
1 answer:
Marina86 [1]3 years ago
4 0

Answer:

Ok, sure

Explanation:

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How much heat is absorbed when 2.8 mol nh4no3 is dissolved in water? the heat of solution of nh4no3 is 25.4 kj/mol.
Kay [80]

The heat absorbed when 2.8 mol NH₄NO₃  is dissolved in water is 71.96 kJ.

<h3>What is heat?</h3>

Heat is the transportation of energy to or from a thermodynamic system.

By the formula of heat

\rm (n) \times (delta\;Hrxn) = (qrxn)

Where n = moles

Delta Hrxn is molar heat

q = heat

Putting the values in the equation

\rm qrxn = (2.8 mol) \times(25.7 kJ/mol) = 71.96 kJ

Thus, the heat absorbed when 2.8 mol NH₄NO₃  is dissolved in water is 71.96 kJ.

Learn more about heat

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A pink roses are formed when red roses are mated with white roses.
Gre4nikov [31]

Answer:

true

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3 years ago
It’s normal to feel nervous during an interview.
anyanavicka [17]

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3 years ago
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Which geographic problem contributed to napoleon's fall from power?
emmainna [20.7K]
The unsuccessful winter campaign in Russia exposed Napoleon's army to extreme cold and The French army's inability to master guerilla warfare led to its defeat in the Peninsula War.
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2 years ago
Newton’s law of cooling states that for a cooling substance with initial temperature t0, the temperature t(t) after t minutes ca
antoniya [11.8K]

The cooling rate of the substance is approximately 0.0732.

According to the statement, the Newton's law of cooling is defined by the following formula:

T(t) = T_{s} + (T_{o}-T_{s})\cdot e^{-k\cdot t} (1)

Where:

  • T_{s} - Final temperature, in degrees Celsius.
  • T_{o} - Initial temperature, in degrees Celsius.
  • t - Time, in minutes.
  • k - Cooling rate, in \frac{1}{min}.
  • T(t) - Current temperature, in degrees Celsius.

Please notice that substance reaches thermal equilibrium when T(t) = T_{s}, that is when temperature of the substance is equal to the temperature of surrounding air.

If we know that T_{o} = 80\,^{\circ}C, t = 15\,min, T_{s} = 50\,^{\circ}C and T(15) = 60\,^{\circ}C, then the cooling rate of the substance is:

60 = 50 + (80 - 50)\cdot e^{-15\cdot k}

\frac{60-50}{80-50}= e^{-15\cdot k}

\frac{1}{3} = e^{-15\cdot k}

k = -\frac{1}{15}\cdot \ln \frac{1}{3}

k \approx 0.0732

The cooling rate of the substance is approximately 0.0732.

To learn more on Newton's law of cooling, we kindly invite to check this verified question: brainly.com/question/13748261

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