Answer
\((y + 3) (y^{2} - 3 y + 9) V)
Explanation
Explanation
Detail ste
Apply \(a^3\pm b^3=(a\pm b)(a^2\ mp ab+b^2)V : \((y + 3) (y^[2} - y \times 3 + 3^{2}) V
Multiply the monomials: \((y + 3) (y^{2} -3y + 3^{23) V
Calculate the power: \((y + 3) (y^{2} - 3 y + 9) V
The magnitude of an object's charge can either increase or decrease the attraction/ repulsion between another object. The larger the difference of the two object's charges, the stronger opposite charges attract, and the stronger like charges repel.
Answer:
9/5
Explanation:
original fraction : x/y
new fraction = .9x/(.5y)
= 9x/5y
(9x/5y) / (x/y)
= 9x/5y * y/x
= 9/5
= 1.8
so it increased by 80%
e.g suppose we had 100/200 or 1/2
new fraction = 90/100 or 9/10
new ratio = (9/10) / (1/2)
= 9/5
Is this supposed to be a fragment or sentence type of question? If so
It’s fragment
Answer:
it make the relationship last long something like that
