The first law here is Charles's law and the new volume will be 285.08 mL
Converting degree celsius to kelvin when solving gas laws problem.
kelvin = degree celsius + 273.15
Kelvin = 19 + 273.15 = 292.15 K
Kelvin = 60 + 273.15 = 333.15 K
Given Data:
V1 (initital volume) = 250 ml
T1 (initial temperature) = 19°c or 292.15 K
V2 (final volume) = unknwon ?
T2 (final temperature) = 60°c or 333.15 K
Charles' law which states that volume is directly proportional to temperature when the amount and pressure of the gas are constant.
Applying the formula, we get
V2 = V1T2 / T1
= 250 ml × 333.15 K / 292.15 K (cancel kelvin unit)
= 83287.5 ml / 292.15
= 285.08 ml
The new volume will be 285.08 ml
brainly.com/question/16927784
#SPJ9
From the data obtained from the tests, the actual boiling point lies between 34°C and 40°C.
The boiling point of a substance is the temperature at which the pressure of the substance becomes equal to atmospheric pressure. Pure substances have a sharp boiling point while impure substances boil over a temperature range.
In this case, the boiling point of the substance after 10 tests is obtained as 37+/−3°C. This implies that the actual boiling point lies between 34°C and 40°C.
Learn more: brainly.com/question/8646601
11 a- ions would exist in the solution, they can carry charges.
B-solids that are neutral, they wouldn't conduct much of a current.
Answer:
709 g
Step-by-step explanation:
a) Balanced equation
Normally, we would need a balanced chemical equation.
However, we can get by with a partial equation, as log as carbon atoms are balanced.
We know we will need an equation with masses and molar masses, so let’s <em>gather all the information</em> in one place.
M_r: 30.07 236.74
C₂H₆ + … ⟶ C₂Cl₆ + …
m/g: 90.0
(i) Calculate the moles of C₂H₆
n = 90.0 g C₂H₆ × (1 mol C₂H₆ /30.07 g C₂H₆)
= 2.993 mol C₂H₆
(ii) Calculate the moles of C₂Cl₆
The molar ratio is (1 mol C₂Cl₆/1 mol C₂H₆)
n = 2.993 mol C₂H₆ × (1 mol C₂Cl₆/1 mol C₂H₆)
= 2.993 mol C₂Cl₆
(iii) Calculate the mass of C₂Cl₆
m = 2.993 mol C₂Cl₆ × (236.74 g C₂Cl₆/1 mol C₂Cl₆)
m = 709 g C₂Cl₆
The reaction produces 709 g C₂Cl₆.
