Answer:
pH = 0.32
Explanation:
To solve this problem we use the <em>Henderson-Hasselbach equation</em>:
- pH = pKa + log
![\frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
In this case
- [A⁻] is [NH₃], as it is the conjugate base of a weak acid
- [HA] is [NH₄⁺], as it is a weak acid
So now we just <u>compute the data in the equation</u>
- pH = 9.24 + log
Answer:
is likely to come from collaborative efforts by technology experts and experts on pollution.
Explanation:
The net osmosis will occur in the direction of the NaCl solution. This is because the solute concentration on that side is greater than that of the glucose solution. Osmosis is the process by which liquids move through semi permeable membrane from the region of lower concentration to the region of higher concentration.
Thus the water is going to move from the glucose solution into the NaCl solution.<span />
Answer:
1) B. increases
2) B. greater
3) C. Both A and B are correct
4) Activation energy
Explanation:
The rate of a chemical reaction is depend on temperature. If temperature increases, the chemical reaction also increases and vice versa. Fast reaction means which is completely in less time. So atoms in fast reaction have great activation energy and slow reaction have less activation energy. Collision occurs when the particles have energy to move and they collide in proper direction.
<h3>
Answer:</h3>
89.88° C
<h3>
Explanation:</h3>
<u>We are given;</u>
- Mass of gold cylinder as 75 g
- specific heat of gold is 0.129 J/g°C
- Initial temperature of gold cylinder is 65°C
- Mass of water is 500 g
- Initial temperature of water is 90 °C
We are required to calculate the final temperature;
- We know that Quantity of heat is given by the product of mass, specific heat capacity and change in temperature.
<h3>Step 1: Calculate the quantity of heat absorbed by the Gold cylinder</h3>
Assuming the final temperature is X° C
Then; ΔT = (X-65)°C
Therefore;
Q = 75 g × 0.129 J/g°C × (X-65)°C
= 9.675X - 628.875 Joules
<h3>Step 2: Calculate the quantity of heat released by water</h3>
Taking the final temperature as X° C
Change in temperature, ΔT = (90 - X)° C
Specific heat capacity of water is 4.184 J/g°C
Therefore;
Q = 500 g × 4.184 J/g°C × (90 - X)° C
= 188,280 -2092X joules
<h3>Step 3: Calculate the final temperature, X°C</h3>
we know that the heat gained by gold cylinder is equal to the heat released by water.
9.675X - 628.875 Joules = 188,280 -2092X joules
2101.675 X = 188908.875
X = 89.88° C
Thus, the final temperature is 89.88° C
