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sergey [27]
3 years ago
9

What happens when the force of friction is more than the force of a moving object?

Physics
2 answers:
ycow [4]3 years ago
7 0

Inertia is a force which brings all objects to a rest position. Fast-moving objects have more inertia than slow-moving objects. False - The speed of an object has no impact upon the amount of inertia that it has. Mostly True - Two objects of the same mass can weigh differently if they are located in different locations.

I don't know if this will help

Vinvika [58]3 years ago
3 0
You push a hockey puck on the smooth ice, after a few feet the puck runs into a mound of slush missed by the zamboni (friction increases). What happens to the puck??
You can do this...
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A brick is released with no initial speed from the roof of a building and strikes the ground in 1.80 s , encountering no appreci
Mars2501 [29]
<span>Kinematics is used in this problem. The mass does not matter here because the question is mass independent. vi = 0 vf = x d = ? d = vi + 1/2 a t^2 d = 0 + 1/2 (9.8) (1.8)^2 d = 15.9 m (counting sig figs)</span>
8 0
4 years ago
Please help me please help
Anna [14]

Answer:

2.12x 10 -3

Explanation:

i dont really have explanation but like that's how it works

5 0
3 years ago
a 300-gram toy car and a 500-gram toy car are sitting on a shelf that is 2 meters highter than the floor. by what percent is the
andre [41]
We are given:

m1 = 300 grams
m2 = 500 grams
h1 = h2 = 2 meters

We have to determine the potential energy of both toy cars:

PE = mgh
PE1 = m1gh1
PE1 = 300 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE1 = 5.886 Joules

PE2 = m2gh2
PE2 = 500 grams/1000g/kg * 9.81 m/s^2 * 2 meters
PE2 = 9.81 Joules

PE2 - PE1 / PE2

9.81 - 5.886 Joules / 9.81 joules * 100 = 40.0%

Therefore, the 500-gram car is greater by 40% in terms of potential energy than the 300-gram car. This is because mass is directly proportional to the potential energy of an object. 

7 0
3 years ago
Read 2 more answers
A reconnaissance plane flies 404 km awayfrom its base at 730 m/s, then flies back to its base at 1095 m/s.What is it’s average s
elena-14-01-66 [18.8K]

The average speed of the plane is 875.999 m/s.

Average speed can be defined as the ratio of total distanced travelled by the object to that of total time taken to cover the distance.

Mathematically, Average speed = Av = \frac{Total Distance}{Total Time}

According to the question,

Speed of the plane away from its base V₁ = 730 m/s

Speed of the plane when it flies back V₂ = 1095 m/s

Plane flies the distance D = 404 km

Total Distance covered by the plane S = 404 * 2 km

(because the distance travelled by the plane when going away from the base and then flying back to the base is same)

Therefore S = 808 km = 808 ˣ 10³ m

Time taken by the plane while flying away from the base T₁ = \frac{D}{V1}

T₁ =  \frac{404000}{730} = 553.425 s

Time taken by the plane while flying back to the base T₂ = \frac{D}{V2}

T₂ =  \frac{404000}{1095} = 368.949s

Total Time T = T₁ + T₂ = 922.375 s

Therefore  Av = \frac{Total Distance}{Total Time}

= \frac{D}{T} m/s

=  \frac{808000}{922.375}  m/s

= 875.999 m/s

The average speed of the plane will be 875.999 m/s.

To know more about Average speed,

brainly.com/question/28641761

#SPJ1

7 0
1 year ago
Please awnser and show the ways​
topjm [15]

Answer:

Answers in solutions.

Explanation:

<u>Question 6:</u>

The density of gold is 19.3 g/cm³

The density of silver is 10.5 g/cm³

  • The density of the substance in Crown A;

Density = mass ÷ volume = \frac{1930}{100} = 19.3 g/cm³

Since the density of gold, given, is 19.3 g/cm³ and the density of the substance in Crown A has a density of 19.3 g/cm³ , then that substance must be gold.

  • The density of the substance in Crown B;

Density = mass ÷ volume = 1930 ÷ 184 = 10.48913043  g/cm³ ≈ 10.5 g/cm³  (answer rounded up to one decimal place)

Since the density of the substance in Crown B is approximately equal to 10.5 g/cm³ , then that substance is Silver.

  • The density of substance in Crown C;

Density = mass ÷ volume = 1930g ÷ 150cm³ = 12.86666667 ≈ 12.9 cm³ (answer rounded up to one decimal place)

<h3><u>The density of the mixture:</u></h3><h3 />

For 2 cm³ of the mixture, its mass equal 19.3 g + 10.5 g = 29.8 g

∴ for 1 cm³ of the mixture, its mass equal to \frac{29.8}{2} = 14.9 g

Hence the density of the mixture = 14.9 g/cm³ and is not equal to the density of the substance in Crown C.

* Crown C is not made up of a mixture of gold and silver.

<u>Question 7:</u>

<u />

  • An empty masuring cylinder has a mass of 500 g.
  • Water is poured into measuring cylinder until the liquid level is at the 100 cm³ mark.
  • The total mass is now 850 g

The mass of water that occupied the 100 cm³ space of the container = total mass - mass of the empty container = 850 g - 500 g = 350 g

Density of the liquid (water) poured into the container = mass ÷  volume = 350 g ÷ 100 cm³ = 3.5g/cm³

<u>Question 8:</u>

<u />

A tank filled with water has a volume of 0.02 m³

(a) 1 liter = 0.001 m³

How many liters? = 0.02 m³ ?

Cross multiplying gives:

\frac{0.02 * 1}{0.001} =  20 liters

(b) 1 m³ = 1,000,000 cm³

0.02 m³ = how many cm³ ?

Cross-multiplying gives;

\frac{0.02 * 1,000,000}{1} = 20,000 cm³

(c) 1 cm³ = 1 ml

∴ 0.02 m³ of the water = 20,000 cm³ = 20,000 ml

<u>Question 9:</u>

<u />

Caliper (a) measurement = 3.2 cm

Caliper (b) measurement = 3 cm

<u>Question 10:</u>

<u />

  • A stone is gently and completely immersed in a liquid of density 1.0 g/cm³
  • in a displacement can
  • The mass of liquid which overflow is 20 g

The mass of the liquid which overflow = mass of the stone = 20 g

1 gram of the liquid occupies 1 cm³ of space.

20 g of the liquid will occupy; \frac{20 * 1}{1} = 20 cm³

(a) Since the volume of the water displaced is equal to the volume of the stone.

∴ The volume of the stone = 20 cm³

(b) Mass = density ×  volume

Density of the stone = 5.0 g/cm³

Volume of the stone = 20 cm³

Mass of the stone = 5 g/cm³ × 20 cm³ = 100 g

7 0
3 years ago
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