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beks73 [17]
3 years ago
13

the rapid movement of gas molecules can be explained because gasses have size particles and exert attraction for other gas parti

cles
Physics
1 answer:
serg [7]3 years ago
6 0

The rapid movement of gas molecules can be explained because gasses have small size particles and exert little attraction for other gas particles.

Explanation

The particles present in the gas are loosely packed and can move freely inside when compared to the particles present in both liquid and solid state.

Therefore, gas particles have high inter-molecular space.

Also, as these gas particles are loosely packed, the force of attraction between each molecule is less.

To sum up, the particles present have high inter-molecular space and low inter-molecular force of attraction.

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A train moving at a constant speed on a surface inclined upward at 10.0° with the horizontal travels a distance of 400 meters in
Amiraneli [1.4K]
If the velocity of the train is v=s/t, where s is the distance and t is time, then v=400/5=80m/s. To get the vertical component of the velocity we need to multiply the velocity v with a sin(α): Vv=v*sin(α), where Vv is the vertical component of the velocity and α is the angle with the horizontal. So:

Vv=80*sin(10)=80*0.1736=13.888 m/s. 

So the vertical component of the velocity of the train is Vv=13.888 m/s.
7 0
3 years ago
If a truck runs into a wall and stops, the truck loses momentum. Because
nignag [31]
The momentum goes to the wall
6 0
3 years ago
A hoop (I = MR2) of mass 3 kg and radius 1.1 m is rolling at a center-of-mass speed of 11 m/s. An external force does 842 J of w
Scilla [17]

Answer:

v_f = 20 m/s

Explanation:

Since the hoop is rolling on the floor so its total kinetic energy is given as

KE = \frac{1}{2}mv^2 + \frac{1}{2} I\omega^2

now for pure rolling condition we will have

v = R\omega

also we have

I = mR^2

now we will have

KE = \frac{1}{2}mv^2 + \frac{1}{2}(mR^2)\frac{v^2}{R^2}

KE = mv^2

now by work energy theorem we can say

W = KE_f - KE_i

842 J = mv_f^2 - mv_i^2

842 = 3(v_f^2) - 3\times 11^2

now solve for final speed

v_f = 20 m/s

3 0
3 years ago
redacteaza un text in care sa iti exprimi parerea in legaturacurtamentul golegilor din textul oracolul
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Answer:

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Explanation:

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4 0
3 years ago
Planet A has a mass of 2.25 x 1020 kg, while planet B has a
denis23 [38]

The gravitational attraction between two planets is  4905.95 N

<h3>What is gravitational attraction?</h3>

When two objects with masses are placed at a distance, there will an attractive force acting between them.

According to the Newton's law of gravitation, gravitational force is

F = Gm₁m₂ /r²

where r is the distance between the masses m₁ and m₂ and  G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²

Substitute the values into the expression, we get

F =  6.67 x 10⁻¹¹ x  2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²

F= 4905.95 N

Thus, the gravitational attraction between two planets is  4905.95 N.

Learn more about gravitational attraction.

brainly.com/question/19822389

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6 0
2 years ago
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