Answer:
0.36 A.
Explanation:
We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:
Resistor 1 (R₁) = 35 Ω
Resistor 2 (R₂) = 20 Ω
Equivalent Resistance (Rₑq) =?
Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:
Rₑq = (R₁ × R₂) / (R₁ + R₂)
Rₑq = (35 × 20) / (35 + 20)
Rₑq = 700 / 55
Rₑq = 12.73 Ω
Next, we shall determine the total resistance in the circuit. This can be obtained as follow:
Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω
Resistor 3 (R₃) = 15 Ω
Total resistance (R) in the circuit =?
R = Rₑq + R₃ (they are in series connection)
R = 12.73 + 15
R = 27.73 Ω
Finally, we shall determine the current. This can be obtained as follow:
Total resistance (R) = 27.73 Ω
Voltage (V) = 10 V
Current (I) =?
V = IR
10 = I × 27.73
Divide both side by 27.73
I = 10 / 27.73
I = 0.36 A
Therefore, the current is 0.36 A.
Answer:
the pressure at the bottom is approximately 103264 Pa
Explanation:
From Pascal's law, the pressure at the bottom of the container is the pressure from the atmosphere and the columns of water and olive , therefore
Pressure at the bottom = Pressure at the surface of the liquid ( atmospheric pressure) + pressure of the column of water + pressure of the column of olive oil
since
- Pressure at the surface of the liquid = atmospheric pressure = 101325 Pa
- pressure of the column of water = density of water * gravity * level of water
= 1000 kg/m³ * 9.8 m/s² * 0.12 m = 1176 Pa
- pressure of the column of olive oil= density of olive oil* gravity * level of olive oil = 916 kg/m³ * 9.8 m/s² * 0.085 m = 763 Pa
therefore
Pressure at the bottom = 101325 Pa + 1176 Pa + 763 Pa = 103264 Pa
density of olive oil was taken from internet sources ( we can check that is lower than the one of water, and thus it floats )
The distance from observer A of intensity of sound 59 db is 28.64 m and the distance from observer B of intensity of sound 83 db is 11.36m
Explanation:
Let's solve this problem in parts
let's start by finding the intensity of the sound in each observer
observer A β = 59 db
β = 
where I₀ = 
W / m²
= 
W / m²
Similarly for Observer b 
now we use that the emitted power that is constant is the intensity over the area of the sphere where the sound is distributed
P = I A
therefore for the two observers
the area of a sphere is
we substitute the above formula, we get
Let us call the distance from the observer A be to stereo speaker = x, so the distance from the observer B to the stereo speaker = 40- x; we substitute
after solving the above equation we get x = 28.64 m
This is the distance of observer A
similarly The distance from observer B is 35 - x
= 40 - 28.64
= 11.36m
To know more about intensity of sound with the given link
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Answer:
Explanation:
The process during which pressure remains constant is called an isobaric process.
The reason behind the barking of the group of neighborhood dogs could be <u>Territorial/Protective</u> or <u>Alarm/Fear</u>.
What is bark or barking?
Dogs are known for making the most prevalent barking noises. Wolves, coyotes, foxes, seals, and barking owls are a few other creatures that make this sounds. The most typical onomatopoeia for this sound in English, particularly for large dogs, is "woof." The word "bark" can also be used to describe the sound made by numerous canids. A bark is a brief vocalization, as per the researchers at the University of Massachusetts Amherst.
Territorial/Protective: When a person or another animal enters their perceived area, your dog may bark excessively, depending on the breed. The barking frequently gets louder as the threat draws closer. When your dog barks in this manner, he will appear vigilant and sometimes even hostile.
Alarm/Fear: Some dogs will bark in alarm or fear at any sound or item that draws their attention or alarmed them. It's not just in their home country where this can occur. When they are afraid, their tails will be tucked and their ears will be pulled back.
To know more about bark, go to link
brainly.com/question/5082728
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