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Afina-wow [57]
3 years ago
15

Someone do 5 plss:)))​

Chemistry
1 answer:
eduard3 years ago
5 0

Answer: The answer is B

Explanation: Looking at the table given, the more wire loops you put on the nail, the more paperclips that it can hold. Meaning the electromagnet gets stronger the more loops you put on the nail

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How do cm3 compare to mililiters
azamat
Cm^3=1cm*1cm*1cm
=10mm*10mm*10mm
=1000 mm^3
4 0
3 years ago
Name ways we use technology in inner and outer space<br> 8th grade science btw
Anna71 [15]

Answer:

Explanation:

Many common everyday services such as weather forecasting, remote sensing, satellite navigation systems, satellite television, and some long-distance communications systems critically rely on space infrastructure. ... Of the sciences, astronomy and Earth science benefit from space technology am in 6th grade btw

5 0
3 years ago
3 C2H2(g) → C6H6(g) What is the standard enthalphy change ΔHo, for the reaction represented above? (ΔHof of C2H2(g) is 230 kJ mo
masha68 [24]

Answer: The standard enthalpy change  is -607kJ

Explanation:

The given balanced chemical reaction is,

3C_2H_2(g)\rightarrow C_6H_6(g)

First we have to calculate the enthalpy of reaction (\Delta H^o).

\Delta H^o=H_f_{product}-H_f_{reactant}

\Delta H^o=[n_{C_6H_6}\times \Delta H_f^0_{(C_6H_6)}]-[n_{C_2H_2\times \Delta H_f^0_{(C_2H_2)}]

where,

We are given:

\Delta H^o_f_{(C_2H_2)}=230kJ/mol\\\Delta H^o_f_{(C_6H_6)}=83kJ/mol

Putting values in above equation, we get:

\Delta H^o_{rxn}=[(1\times 83)]-[(3\times 230)]=-607kJ

The standard enthalpy change  is -607kJ

7 0
4 years ago
When bsia is assembled as an octamer, what is most likely to be true regarding l76, l77, and l79?
telo118 [61]

The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

<h3>What is entropic penalty?</h3>

The entropic penalty in regards to ordered water is known to be one that tells or account  for any form of  weaker binding of the antibiotic novobiocin to what we call resistant mutant of DNA gyrase.

Note that in regards to the scenario above, the Entropic penalty is seen as the thermodynamically disfavored needs that is required in forming a cage of polar solvent molecules that is known to be seen around surface that has exposed hydrophobic potion of a molecule.

Hence, The option that is most likely to be true regarding L76, L77, and L79  is that option B: The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

Learn more about octamer from

brainly.com/question/13198179

#SPJ1

See full question below

When Bs1A is assembled as an octamer, what is most likely to be true regarding L76, L77, and L79?

A. They are oriented toward the solvent-exposed exterior of the protein assembly.

B. The assembly would incur an entropic penalty if they occupied a solvent-exposed site.

C. Unlike in a monomer, they are not situated within the hydrophobic cap.

D. Their physiochemical properties are not substantially dependent on their hydrophobicity

5 0
2 years ago
Select the correct answer. Given: 2LiBr Ba → BaBr2 2Li In this chemical reaction, 325 grams of barium (Ba) react completely. How
leva [86]
The answer is b 2.37
7 0
2 years ago
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