Answer:
NaOH(aq) is a Base.
Explanation:
Those substances which give or release
ions in aqueous solution are called as the Arrhenius Bases.
In the aqueous solution, NaOH dissociates as follows -
↔ 
If it reacts with a strong acid HCl, the chemical equation for this reaction will be as follows -

The chemical reaction between the reactants:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Explanation:
We have the following chemical reaction:
3 AgNO₃ (aq) + FeCl₃ (aq) → 3 AgCl (s) + Fe(NO₃)₃ (aq)
Complete ionic equation:
3 Ag⁺ (aq) + 3 NO₃⁻ (aq) + Fe³⁺ (aq) + 3 Cl⁻ (aq) → 3 AgCl (s) + Fe³⁺ (aq) + 3 NO₃⁻ (aq)
We remove the spectator ions and we get the net ionic equation:
Ag⁺ (aq) + Cl⁻ (aq) → AgCl (s)
where:
(aq) - aqueous
(s) - solid
Learn more about:
net ionic equation
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Answer:
1-(tert-butoxy)-2-methylpropane
Note: there is a mistake in formula, the correct formula is (CH₃)₂-CH-CH₂-O-C(CH₃)₃ not (CH₃)₂-CH-CH₂-O(CH₃)₃, because oxygen is a divalent compound.
Explanation:
<em>Structural formula is attached</em>
IUPAC naming rules
1. start numbering the chain from the functional group. In this compound we start from oxygen side.
2. Here we can see that at position 1 there is an oxy group along with a tertiary carbon having three methyl groups. So we write it as 1-tert-butoxy. Which means that there is a methoxy group at position 1 along with a tertiary carbon.
3. At position 2 we can see that there is a methyl group attached to the main chain, so we write it as 2-methyl.
4. Now we count the total number of carbons in the main chain. As we can see that there are 3 carbons in the remaining or parent chain, so we write it as propane
5. So the IUPAC name of the compound will be 1-(tert-butoxy)-2-methylpropane