pretty sure its B thank me later
Explanation:
Copper(II) sulfide reacts with oxygen gas to give solid copper(II) oxide and sulfur trioxide gas.
The reaction is given as:

When 1 mol copper(II) sulfide react with 2 moles of oxygen gas it gives 1 mol of solid copper(II) oxide and 1 mol of sulfur trioxide gas
The gas formed in above reaction that is sulfur trioxide reacts with water to give sulfuric acid or hydrogen sulfate.
The reaction is given as:

1 mol of sulfur trioxide gas reacts with 1 mol of liquid water to produce 1 molo of liquid hydrogen sulfate or sulfuric acid
system will shift the equilibrium to the right, towards the side of the products
Answer:
P = 5.14ATM
Explanation:
Number of moles = 0.108moles
Temperature (T) = 20°C = 20 + 273.15 = 293.15K
Volume V = 0.505L.
Pressure (P) = ?
R = 0.082J/mol.K
From ideal gas equation,
PV = nRT
P = nRT / V
P = (0.108 * 0.082 * 293.15) / 0.505
P = 2.596 / 0.505
P = 5.14ATM
The pressure of the gas is 5.14ATM