Answer:
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Explanation:
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The answer would be C. Amplitude
Answer:
Oxidation is defined as the chemical process in which substance loses electron and hydrogen or gain oxygen while in the process of reduction, substance gains electron and hydrogen or loses oxygen.
So, from the given equation:
a. It is an oxidation reaction as Rb loses one elctron.
b. It is a reduction reaction as Te gains two electrons and become Te2-
c. It is a reduction reaction as H atom gains electrons.
d. It is an oxidation reaction as P loses 3 electrons.
<h3>
Answer:</h3>
1026.05 kJ
<h3>
Explanation:</h3>
- The Quantity of heat is calculated by multiplying the mass of a substance by specific heat capacity and the change in temperature.
- However, condensation takes place at a constant temperature.
- Therefore, Quantity of heat is calculated by multiplying mass by the latent heat of vaporization.
In this case we are given;
Mass of steam as 454 g
To calculate the amount of heat released we must know the value of latent heat of vaporization;
The latent heat of vaporization of steam is 2260 J/g
Therefore;
Heat released, Q = 454 g × 2260 J/g
=1026040 Joules
But, 1000 joules = 1 kilo-joules
Thus, Q = 1026.04 kJ
Hence, the amount of heat released is 1026.05 kJ
Answer:
there is 2% of hydrogen and 98% of nitrogen (mass percent)
Explanation:
assuming ideal gas behaviour
P*V=n*R*T
n= P*V/(R*T)
where P= pressure=1.02 atm , V=volume=7.47 L , T=absolute temperature= 296 K and R= ideal gas constant = 0.082 atm*L/(mole*K)
thus
n= P*V/(R*T) = 1.02 atm*7.47 L/( 296 K * 0.082 atm*L/(mole*K)) = 0.314 moles
since the number of moles is related with the mass m through the molecular weight M
n=m/M
thus denoting 1 as hydrogen and 2 as nitrogen
m₁+m₂ = mt (total mass)
m₁/M₁+m₂/M₂ = n
dividing one equation by the other and denoting mass fraction w₁= m₁/mt , w₂= m₂/mt , w₂= 1- w₁
w₁/M₁+w₂/M₂ = n/mt
w₁/M₁+(1-w₁) /M₂ = n/mt
w₁*(1/M₁- 1/M₂) + 1/M₂ = n/mt
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂)
replacing values
w₁= (n/mt- 1/M₂) /(1/M₁- 1/M₂) = (0.314 moles/3.48 g - 1/(14 g/mole)) /(1/(1 g/mole)-1/(14 g/mole))= 0.02 (%)
and w₂= 1-w₁= 0.98 (98%)
thus there is 2% of hydrogen and 98% of nitrogen
