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SSSSS [86.1K]
3 years ago
9

After years of maintaining a steady population of 32,000, the population of a town begins to grow exponentially. After 1 year an

d an increase of 8% per year, the population is 34,560. Which equation can be used to predict, y, the number of people living in the town after x years? (Round population values to the nearest whole number.)
Mathematics
2 answers:
elixir [45]3 years ago
6 0

Answer:

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08)x

Step-by-step explanation:

Hi, to answer this question we have to analyze the information given:

  • <em>Initial population: 32,000 </em>
  • <em>Growth per year: 8% </em>
  • <em>Years: x </em>

So, to obtain "y" (the number of people living in the town after x years), we have to multiply the initial population by 1+ 0.08 (the growth rate is 8%/100=0.08 and the original value) and the number of years (x).

Mathematically speaking:

y = 32,000 (1+0.08) x

y= 32,000 (1.08) x

The equation used to predict the number of people living in the town after x years is y = 32,000 (1.08)x

pochemuha3 years ago
5 0

Answer:

A) on Edge2020

Step-by-step explanation:

y = 32,000(1.08)x

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Scott is on his school's academic team. On average, it takes Scott 4 minutes, with a standard deviation of 0.25 minutes, to solv
uysha [10]

Answer:

15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 4 minutes

Standard Deviation, σ = 0.25 minutes

We standardize the given data.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

P(more than 4.25 minutes to solve a problem)

P( x > 4.25) = P( z > \displaystyle\frac{4.25 - 4}{0.25}) = P(z > 1)

= 1 - P(z \leq 1)

Calculation the value from standard normal z table, we have,  

P(x > 4.25) = 1 - 0.8413 = 0.1587 = 15.87\%

Thus,15.87% is the chance that Scott takes more than 4.25 minutes to solve a problem at an academic bowl.

8 0
3 years ago
3. Here is a diagram of a softball field:
Crank

a. Length of the fence around the field = perimeter of quarter circle = 892.7 ft.

b. The area of the outfield is about 39,584 sq. ft..

<h3>What is the Perimeter of a Quarter Circle?</h3>

Perimeter of circle = 2πr

Perimeter of a quarter circle = 2r + 1/4(2πr).

a. The length of the fence around the field = perimeter of the quarter circle fence

= 2r + 1/4(2πr).

r = 250 ft

Plug in the value

The length of the fence around the field = 2(250) + 1/4(2 × π × 250)

= 892.7 ft.

b. Size of the outfield = area of the full field (quarter circle) - area of the infield (cicle)

= 1/4(πR²) - πr²

R = radius of the full field = 250 ft

r = radius of the infield = 110/2 = 55 ft

Plug in the values

Size of the outfield = 1/4(π × 250²) - π × 55²

= 49,087 - 9,503

= 39,584 sq. ft.

Learn more about perimeter of quarter circle on:

brainly.com/question/15976233

4 0
2 years ago
The population of Groverdale is
wolverine [178]

Answer: Yes alaina is correct

Step-by-step explanation: first look at the populations

553,000

535,841    

Tittlehook has a 3 in the ten thousands place whilst groverdale has a 5 in the thousands place.

Hope this helps :)

6 0
3 years ago
What is the answer????????? help
fenix001 [56]
80


adding up the numbers 30,20,5,25

maybe im wrong but i hope it helps...
8 0
3 years ago
your grades on tests 1 2 and 4 are 82 76 and 90. unfortunately you cut the third test and received a 0. If you have one test lef
Dmitrij [34]

Answer:  No, he can't pass the course.

Explanation:

Since we have given that

Marks on tests 1, 2, and 4 are given by

82, 76, 90 respectively.

Unfortunately, he cut the third test and receive a 0.

According to question, we have given that passing grade for the course is 70, and his one test left to take ,

Let the marks obtained in fifth test be x

So,

\frac{82+76+90+0+x}{5}=70\\\\248+x=5\times 70=350\\\\x=350-248\\\\x=102

And it is not possible to get 102 over 100.

so, he can't still pass the course.

Hence, No, he can't pass the course.

8 0
3 years ago
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