Answer:
f(x)=12x
Step-by-step explanation
We know that f(x) is our y-coordinate and x is the x-coordinate
Next we should insert x-6 as x in the equation
This is f(x)=12(x-6)-72
But if you look at this that leads to 12x-72 (ignore y-intercept)
That is our first equation
This means that if you take out -6 from the x
You will get f(x)=12x
(Also do you go to RSM?)
Answer:
momentum
Explanation:
kenetic energy is not conserved so it turns into a different form of energy, this being momentum
0.8=0.8/1=8/10=4/5
not one of them
but,
2/9=0.2222222222
4/9=0.444444444444
7/9=0.7777777777
8/9=0.88888888888
I think you meant 0.8 repeating so
answer is D
I can’t see it sorry maybe it’s my device
Answer:
h(8q²-2q) = 56q² -10q
k(2q²+3q) = 16q² +31q
Step-by-step explanation:
1. Replace x in the function definition with the function's argument, then simplify.
h(x) = 7x +4q
h(8q² -2q) = 7(8q² -2q) +4q = 56q² -14q +4q = 56q² -10q
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2. Same as the first problem.
k(x) = 8x +7q
k(2q² +3q) = 8(2q² +3q) +7q = 16q² +24q +7q = 16q² +31q
_____
Comment on the problem
In each case, the function definition says the function is not a function of q; it is only a function of x. It is h(x), not h(x, q). Thus the "q" in the function definition should be considered to be a literal not to be affected by any value x may have. It could be considered another way to write z, for example. In that case, the function would evaluate to ...
h(8q² -2q) = 56q² -14q +4z
and replacing q with some value (say, 2) would give 196+4z, a value that still has z as a separate entity.
In short, I believe the offered answers are misleading with respect to how you would treat function definitions in the real world.
