Please help me I will give brainliest pls help

Does anyone know how to do this?

Scilla [17]

Wouldn’t number seven be

2a+2b because of the distributive property?

6 0

4 years ago

which expression is equivalent to 18 * 12 A) 12 * 18) B) 10*8*12) C) (10+8) * (10+12). Please hurry

pickupchik [31]

Answer:

12*18

Step-by-step explanation:

18*12 is the same as 12*18 and they both equal 216

8 0

3 years ago

In a survey, 32% of the respondents stated that they talk to their pets on the telephone. A veterinarian believed this result

adoni [48]

Answer:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

Step-by-step explanation:

Data given and notation

n=210 represent the random sample taken

X=61 represent the number of pet owners contacted by telephone

$\hat p=\frac{61}{210}=0.29$ estimated proportion of pet owners contacted by telephone

$p_o=0.32$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportions is lower than 0.32.:

Null hypothesis: $p \geq 0.32$

Alternative hypothesis: $p < 0.32$

When we conduct a proportion test we need to use the z statistic, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.29 -0.32}{\sqrt{\frac{0.32(1-0.32)}{210}}}=-0.932$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of pet owners contacted by telephone is NOT significantly lower than 0.32

3 0

3 years ago

Which relation is a function mastery test

8090 [49]

Answer:

The relation which is a function is the one in which none of the first coordinates repeated.

Step-by-step explanation:

7 0

3 years ago

A library had 570 books when it first opened. A year later, the number of books increased by 30%. How many books were there in t

s344n2d4d5 [400]

Answer: There were 741 books in the library a year later.

Step-by-step explanation:

Given: Total books in library = 570

Number of books increased by 30%.

One year later, Number of books in the library = (Total books in library) + 30% x (Total books in library)

= 570 + (0.30) x (570)

= 570 (1+0.30)

= 570 (1.30)

= 741

Hence, there were 741 books in the library a year later.

3 0

3 years ago