Question

20 POINTS AND BRAINLIEST ONLY FOR CORRECT ANSWER

Answer 1

9514 1404 393

Answer:

  85°

Step-by-step explanation:

Each of the isosceles triangles PAB and QBC has interior base angles of ...

  (180° -80°)/2 = 50°

Then angle PBC is 90° -50° = 40°.

Segments PB and QB are the same length, so triangle PBQ is an isosceles right triangle. This means angle BPQ is 45°. Angle QEB is the sum of the remote interior angles of ∆BEP, so is 45° +40° = 85°.

The acute angle between PQ and BC is 85°.