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3 years ago

Parabola passes through the points (0,5), (1,4), and (2,5). What function does the graph represent?

Mathematics

1 answer:

AfilCa [17]3 years ago

7 0

Answer:

x^2 - 2x + 5 = 0.

Step-by-step explanation:

The (0, 5) is the point where the parabola passes through the y axis (where x = 0), so we can write the equation as

y = ax^2 + bx + 5 where a and b are constants to be found.

Also, since (1, 4) and (2, 5) are points on the curve, substituting, we have the system:

a(1)^2 + 1b + 5 = 4

a(2)^2 + 2b + 5 = 5

Simplify these 2 equations:

a + b = -1 .................(1)

4a + 2b = 0..................(2)

Multiply the first equation by -2:

-2a - 2b = 2 .................(3)

Add (2) + (3):

2a = 2

a = 1.

Substitute a = 1 into (2):-

4*1 + 2b = 0

2b = -4

b = -2.

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PLEASE HELP WITH GRAPH LAST QUESTION I NEED

SVETLANKA909090 [29]

Answer:

$\sf g(x) = -1(x+3)^2 -2$

Explanation:

$\sf original \ graph: \ y=-x^{2}$

the graph is translated 3 units to the left and 2 units down.

vertex: (-3,-2) point: (-1,-6)

$\sf so \ new \ graph :$

$\sf y = a(x-h)^2 +k$

$\sf -6 = a(-1-(-3))^2 -2$

$\sf -6 = 4a -2$

$\sf 4a = -4$

$\sf a = -1$

$\sf equation:$

$\sf y = a(x-h)^2 +k$

$\sf y = -1(x+3)^2 -2$

6 0

2 years ago

Read 2 more answers

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps. Two times Johan’s collectio

MrRissso [65]

The number of postage stamps in John’s collection is 27.

We have given that,

John, Johan, and Jonathan collect postage stamps. Johan and Jonathan have the same number of stamps.

<h3>What is an elimination method?</h3>

The elimination method is the process of eliminating one of the variables in the system of linear equations using the addition or subtraction methods in conjunction with the multiplication or division of coefficients of the variables.

Johan and Jonathan have the same number of stamps.

Let x be the Johan and Jonathan postal stamps.

Let y be the John postal stamps.

Two times Johan’s collection is eleven less than five times John’s collection.

2x = 5y - 11............(1)

Three times Jonathan’s collection is three less than seven times John’s collection.

3x = 7y - 3............(2)

Multiply equation 1 with 3

3(2x = 5y - 11)

⇒ 6x = 15y - 33.........(3)

Multiply equation 2 with 2

2(3x = 7y - 3)

⇒ 6x = 14y - 6.............(4)

Subtract equation 4 from equation 3

⇒ 6x - 6x = 15y - 33 - (14y - 6)

⇒ 0 = y - 27

⇒ y = 27

Hence, the number of postage stamps in John’s collection is 27.

Find more information about the elimination method here

brainly.com/question/13877817

#SPJ1

6 0

1 year ago

Will give brainlisted whoever is correct first. please hurry.

kipiarov [429]

Answer:

32.33 <= m

Step-by-step explanation:

Since we are dealing with below sea level our initial starting point and max level will both be negative values, while our descending rate will also be negative because we are going down. Using the values provided we can create the following inequality...

-400 <= -12m - 12

Now we can solve the inequality to find the max number of minutes that the submarine can descend.

-400 <= -12m - 12 ... add 12 on both sides

-388 <= -12m ... divide both sides by -12

32.33 <= m

3 0

2 years ago

Compound Interest: Hannah is putting 10,000 dollars in the bank for 5 years at 6% p.a every 6 months what is her Final Balance?

8090 [49]

I think you can solve it by doing this:

10(10,000+0.06)= Final Balance

6 months + 6 months = 1 year

^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
She has to pay twice a year

Now that we know that just multiply 2 by 5 and you get 10. 10(10,000+0.06)= Final Balance

So it should be 100000.6

Not sure if that's right so ask someone to check

6 0

3 years ago

Suppose that a large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved. Another br

aliya0001 [1]

Answer:

$A=1500-1450e^{-\dfrac{t}{250}}$

Step-by-step explanation:

The large mixing tank initially holds 500 gallons of water in which 50 pounds of salt have been dissolved.

Volume = 500 gallons

Initial Amount of Salt, A(0)=50 pounds

Brine solution with concentration of 2 lb/gal is pumped into the tank at a rate of 3 gal/min

$R_{in}$ =(concentration of salt in inflow)(input rate of brine)

$=(2\frac{lbs}{gal})( 3\frac{gal}{min})\\R_{in}=6\frac{lbs}{min}$

When the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min.

Concentration c(t) of the salt in the tank at time t

Concentration, $C(t)=\dfrac{Amount}{Volume}=\dfrac{A(t)}{500}$

$R_{out}$ =(concentration of salt in outflow)(output rate of brine)

$=(\frac{A(t)}{500})( 2\frac{gal}{min})\\R_{out}=\dfrac{A}{250}$

Now, the rate of change of the amount of salt in the tank

$\dfrac{dA}{dt}=R_{in}-R_{out}$

$\dfrac{dA}{dt}=6-\dfrac{A}{250}$

We solve the resulting differential equation by separation of variables.

$\dfrac{dA}{dt}+\dfrac{A}{250}=6\\$The integrating factor: e^{\int \frac{1}{250}dt} =e^{\frac{t}{250}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{250}}+\dfrac{A}{250}e^{\frac{t}{250}}=6e^{\frac{t}{250}}\\(Ae^{\frac{t}{250}})'=6e^{\frac{t}{250}}$

Taking the integral of both sides

$\int(Ae^{\frac{t}{250}})'=\int 6e^{\frac{t}{250}} dt\\Ae^{\frac{t}{250}}=6*250e^{\frac{t}{250}}+C, $(C a constant of integration)\\Ae^{\frac{t}{250}}=1500e^{\frac{t}{250}}+C\\$Divide all through by e^{\frac{t}{250}}\\A(t)=1500+Ce^{-\frac{t}{250}}$

Recall that when t=0, A(t)=50 (our initial condition)

$50=1500+Ce^{-\frac{0}{250}}50=1500+Ce^{0}\\C=-1450\\$Therefore the amount of salt in the tank at any time t is:\\A=1500-1450e^{-\dfrac{t}{250}}$

4 0

3 years ago