Let c represent the weight of cashews and p the weight of pecans.
Then c + 10 = total weight of the nut mixture.
An equation for the value of the mixture follows:
$1.50(10 lb) + $0.75c = (c+10)($1.00)
Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:
15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.
Need 20 lb of cashews.
Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.
12 5/25 as a simplified mixed number would be 12 1/5
6/2 is 3 dollars per can of tuna
Adding an outlier would increase n (the number of data points) by 1.
Before that were to happen, the median would be the mean of 61 and 65, or 63.
After that were to happen, the median of the revised data set would be the middle, or 7th, point: 65. So: The IQR would increase.
Answer:
Graph or the problem?
Step-by-step explanation: