Answer:
6 seconds
Step-by-step explanation:
h(x)=-(x-2)^2+16
We want h(x) to be 0 ( that is when the ball hits the ground)
0 = -(x-2)^2+16
Subtract 16 from each side
-16 = -(x-2)^2+16-16
-16 = -(x-2)^2
Divide by -1
16 = (x-2)^2
Take the square root of each side
sqrt(16) = sqrt((x-2)^2)
±4 = x-2
Add 2 to each side
2±4 = x-2+2
2±4 =x
2+4 = x 2-4 = x
6 =x -2 =x
Time cannot be negative so x=6
The answer is -11, if you are adding a negative with a negative if will stay as a negative so you just add the numbers
Answer:
Step-by-step explanation:
Split it into 2 inequalities:
-8 < y + 2x
y + 2x < 14
Isolate y , subtract 2x from first and then from second
-8 -2x < y
y < 14 -2x
Rewrite it so it looks pretty?
y > -2x-8
y < -2x +14
You can use the calculator to graph each inequality.
The solution or the system is the area where the 2 solutions for each line overlap.
