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3 years ago

Y+x2÷2 when x=4 and y=−3.

Mathematics

2 answers:

shtirl [24]3 years ago

5 0

Answer:

The answer is 1.

Step-by-step explanation:

Plug in the values to make the equation -3+4*2/2

According to the order of operations, you should multiply what you can first.

so 4*2 = 8

Then 8 divided by 2 = 8/2=4

Then -3+4=1

statuscvo [17]3 years ago

5 0

Answer:

Step-by-step explanation:

y + x²÷2 when x=4 and y=-3

-3 + 4² ÷ 2

-3 + 16 ÷ 2

-3 + 8

I hoped this helped :)

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mrs_skeptik [129]

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3 years ago

Solve the following differential equation: (1− 5 y +x) dy/dx +y= 5/x −1 .<br><br> C=

Ganezh [65]

Answer:

$y(1+x)+x-5\ln xy=C$

Step-by-step explanation:

Consider the given differential equation is

$(1-\frac{5}{y}+x)\frac{dy}{dx}+y=\frac{5}{x}-1$

$(1-\frac{5}{y}+x)\frac{dy}{dx}=\frac{5}{x}-1-y$

$(1-\frac{5}{y}+x)dy=(\frac{5}{x}-1-y)dx$

Taking all variables on right sides.

$(1-\frac{5}{y}+x)dy-(\frac{5}{x}-1-y)dx=0$

$(-\frac{5}{x}+1+y)dx+(1-\frac{5}{y}+x)dy=0$

Let as assume,

$M=-\frac{5}{x}+1+y$ and $N=1-\frac{5}{y}+x$

Find partial derivatives $\frac{\partial M}{\partial y}$ and $\frac{\partial N}{\partial x}$

$\frac{\partial M}{\partial y}=1$ and $\frac{\partial N}{\partial x}=1$

Since $\frac{\partial M}{\partial y}=\frac{\partial N}{\partial x}$ , therefore the given differential equation is exact.

The solution of the exact differential equation is

$\int Mdx+\int N(\text{without x)}dy=C$

$\int (-\frac{5}{x}+1+y)dx+\int (1-\frac{5}{y})dy=C$

$yx-5\ln x+x+y-5\ln y=C$

$y+x+xy-5\ln x-5\ln y=C$

$y(1+x)+x-5(\ln x+\ln y)=C$

$y(1+x)+x-5\ln xy=C$

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3 years ago

What is the interior angles cut by transversal t.

gregori [183]

Answer:

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3 years ago

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Hatshy [7]

Answer:

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Step-by-step explanation:

the x axis should be labeled hours and the y axis should be labeled amount earned or dollars

the coordinates on the graph should be

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I cannot see the answer choices but I hope this information helps you answer the question

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3 years ago