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2 years ago

Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?

Mathematics

1 answer:

Wewaii [24]2 years ago

3 0

Answer:Rs15

Step-by-step explanation:

150g=150/1000=0.15kg

1kg cost Rs100

0.15kg cost =100 x 0.15=15

150g cost Rs15

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A sporting goods manager was selling a ski set for a certain price. The manager offered the markdowns shown on the right, making

ra1l [238]

Answer:

The original selling price would be $ 515.87 ( approx )

Step-by-step explanation:

Consider the complete question is :

"A sporting goods store manager was selling a ski set for a certain price. The manager offered the markdowns shown, making the one-day sale price of the ski set $325. Find the original selling price of the ski set. It was marked down 10% and 30%"

Suppose x be the original selling price ( in dollars ),

After marking down 10%,

New selling price = x - 10% of x = x - 0.1x = 0.9x

Again after marking down 30%,

Final selling price = 0.9x - 30% of 0.9x

= 0.9x - 0.3 × 0.9x

= 0.9x - 0.27x

= 0.63x

According to the question,

0.63x = 325

$\implies x =\frac{325}{0.63}=\$ 515.87$

Therefore, the original selling price would be $ 515.87.

8 0

3 years ago

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What is (x - 4y) (-3x - 2y) = ?

Artemon [7]

The answer is -3x^2+10xy+8y^2

3 0

3 years ago

What is the factor to change pounds to kilograms

daser333 [38]

Multiply pounds by 2.205

7 0

2 years ago

With reference to the figure, sin X equals? 1.) 0.250 2.)0.447 3.)0.894 4.)1

Flura [38]

Answer:

3.) 0.894

Step-by-step explanation:

✔️First, find BD using Pythagorean Theorem:

BD² = BC² - DC²

BC = 17.89

DC = 16

Plug in the values

BD² = 17.89² - 16²

BD² = 64.0521

BD = √64.0521

BD = 8.0 (nearest tenth)

✔️Next, find AD using the right triangle altitude theorem:

BD = √(AD*DC)

Plug in the values into the equation

8 = √(AD*16)

Square both sides

8² = AD*16

64 = AD*16

Divide both sides by 16

4 = AD

AD = 4

✔️Find AB using Pythagorean Theorem:

AB = √(BD² + AD²)

AB = √(8² + 4²)

AB = √(64 + 16)

AB = √(80)

AB = 8.9 (nearest tenth)

✔️Find sin x using trigonometric ratio formula:

Reference angle = x

Opposite side = BD = 8

Hypotenuse = AB = 8.944

Thus:

$sin(x) = \frac{opp}{hyp} = \frac{8}{8.944} = 0.894$ (nearest thousandth)

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3 years ago

The graphs below have the same shape. What is the equation of the red

anyanavicka [17]

Answer:

Option B is correct .

Step-by-step explanation:

According to Question , both the graph have same shape . If we look at the the first graph it cuts x - axis at (0 , 2) and ( 0 , -2) . Hence x = 2 and -2 are the zeroes of the equation .

And ,the given function is ,

$\implies f(x) = 4 - x^2 \\\\\implies f(x) = 4-x^2=0 \\\\\implies 2^2-x^2=0\\\\\implies (2-x)(2+x) = 0 \\\\\boxed{\red{\bf \implies x = 2 , (-2) }}$

Hence ,we can can see that x = 2 and (-2) are the zeroes of graph. 

This implies that if we know the zeroes , we can frame the Equation.

On looking at second parabola , it's clear that cuts x - axis at ( 1, 0 ) and (-1,0). So , 1 and -1 are the zeroes of the quadratic equation . Let the function be g(x) . Here , a and ß are the zeroes.

$\implies g(x) = (x-\alpha)(x-\beta) \\\\\implies g(x) = (1+x)(1-x) \\\\\boxed{\pink{\bf \implies g(x) = 1 - x^2}}$

Hence option B is correct .

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2 years ago

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Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?​

Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?