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iren2701 [21]
3 years ago
12

Price of 1kg sugar is Rs. 100 calculate the price of 150g sugar?​

Mathematics
1 answer:
Wewaii [24]3 years ago
3 0

Answer:Rs15

Step-by-step explanation:

150g=150/1000=0.15kg

1kg cost Rs100

0.15kg cost =100 x 0.15=15

150g cost Rs15

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2 horses ran from the same place from the at same time one horse ran at 2 miles per second and the other ran at a speed for 18 m
RSB [31]

Answer:

no horse can run 18 miles per second or even 2 miles per second.

Step-by-step explanation:

4 0
3 years ago
Which best describes this triangle?
son4ous [18]
Two sides are the same length one angle measures 90 degrees
7 0
3 years ago
Please answer and explain.
almond37 [142]
Hi there!

10. the number: x

4 more = addition 

5 times = multiplication

less then 54 = 54 >

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Hope this helps!

4 0
3 years ago
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
3 years ago
W^3=125 when w = ...........
blondinia [14]

Answer: w = 5

Step-by-step explanation:

Step 1: Take cube root.

w=(125) ^(1/3)

W = 5

5 0
3 years ago
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