PLEASE HELP ASAP!!!!

Anon25 [30]

5 0

2 years ago

The graph of a function is shown: scatterplot of the following points: negative 3 and 2, negative 2 and negative 1, 2 and negati

Maurinko [17]

Let's assign these coordinate points as P1(-3,2), P2(-2,-1), P3(2,-1) and P4(3,3). When you plot these points (shown in the picture), they are widely scattered. Therefore, they must not be a trend. Since you forgot to include the options, I would just make a smart guess that these coordinates form a shape which is quadrilateral. I just have to make use of what I have. From the given, I could possibly determine the area of the quadrilateral.

First, you need to plot the points in a cartesian plane as what is shown at the top of the attached picture. Then, you make a matrix wherein the x coordinates are placed in the first row, and the y coordinates in the second row (shown as the black box in the picture). Make sure that you arrange the points in order (whether clockwise or counterclockwise).

Once you create the matrix, you find its determinant. This is done by multiplying the numbers diagonally. The equation will be: arrow down - arrow up. The solution is as follows:

Determinant = [(-3×-1) + (-2×-1) + (2×3)] - [(2×-2) + (-1×2) + (-1×3)] = 20

Then, we use the equation for area of any polygon: A = 1/2*determinant
A = 1/2*20 = 10 square units

Thus, the output of the point plotted together creates a quadrilateral with an area of 10 square units.

5 0

3 years ago

In an anthropology class there are 77 anthropology majors and 1414 non-anthropology majors. 55 students are randomly selected to

Nata [24]

Answer:

P = 0.9989

Step-by-step explanation:

In order to do this, I will use the following numbers to make the calculations easier. In this case, We'll say that we have 7 majors and 14 non majors anthopology to present a topic.

This means that in the class we have 21 students.

Now, we choose 5 of them, and we want to know the probability that 1 of them is non major.

First, we need to calculate the number of ways we can select the students in all cases, and then, the probability.

First, we'll use the combination formula, to calculate the number of ways we can select the 5 students out of the 21. We use combination, because it does not matter the order that the students are selected.

C = m! / n!(m - n)!

Where:

m: number of students

n: number of selected students out of m.

With this expression we will calculate first, how many ways we can choose the 5 students out of 21:

C1 = 21! / 5!(21-5)! = 20,349

Now let's calculate the number of ways you can get the all 5 students are non majors:

C2 = 14! / 5!(14 - 5)! = 2002

Now we need to know the number of ways we can get 4 non majors and 1 major:

C3 = C3' * C3''

C3' represents the number of ways we can get 4 non majors and the C3'' represents the number of ways we can get 1 major.

C3' = 14! / 4!(14 - 4)! = 1,001

C3'' = 7! / 1!(7 - 1)! = 7

C3 = 1001 * 7 = 7,007 ways to get 4 non majors and 1 major

Now the way to get 3 non majors and 2 majors, we do the same thing we do to get 4 non majors and 1 major, but changing the numbers. Then the way to get 2 non majors and 3 majors, and finally 1 non major and 4 majors:

3 non majors and 2 majors:

C4 = C4' * C4'' = [14! / 3!(14 - 3)!] * [7! / 2!(7 - 2)!] = 7,644

2 non majors and 3 majors:

C5 = C5' * C5'' = [14! / 2!(14 - 2)!] * [7! / 3!(7 - 3)!] = 3,185

1 non major and 4 majors:

C6 = C6' * C6'' = [14! / 1!(14 - 1)!] * [7! / 4!(7 - 4)!] = 490

Finally to know the probability of getting 1 out of the 5 to be non major, we have to sum all the previous results, and divide them by the ways we can choose the 5 students (C1):

P = 2,002 + 7,007 + 7,644 + 3,185 + 490 / 20,349

P = 0.9989

5 0

3 years ago

5) Ziegler is using paper for an art project

lord [1]

Answer:

9.5 * 10^-2 mm

Step-by-step explanation:

To find the total thickness, we proceed to add the two thickness that we have

Mathematically, this will be;

0.025 mm + 7 * 10^-2 mm

7 * 10^-2 mm = 0.07

So we have;

0.025 mm + 0.07 mm = 0.095

In scientific notation, this is 9.5 * 10^-2 mm

6 0

3 years ago

Help due soon plss!!!!

Gelneren [198K]

Answer:

Cube=150cm^2

Triangular Prism=228ft^2

Step-by-step explanation:

Cube

$A=6a^2=6*5^2=150cm^2$

Triangular prism

Using these formulas

$A=2A_{B}+(a+b+c)h\\A_{B} =\sqrt{s(s*a)(s*b)(s*c)} \\s=\frac{a+b+c}{2}$

Solving for A

$A=ah+bh+ch+\frac{1}{2} \sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4} \\=6.5*11+5*11+6.5*11+\frac{1}{2} *\sqrt{-6.5^4+2*(6.5*5)^2+2*(6.5*6.5)^2-5^4+2*(5*6.5)^2-6.5^4} \\=228ft^2$

5 0

2 years ago