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statuscvo [17]
3 years ago
15

1) The ratio 20 minutes to 1hour can be written 1:n. What is the value of n.

Mathematics
1 answer:
yarga [219]3 years ago
6 0

Answer:

n=3 x=225,000km

Step-by-step explanation:

1hour=60mins

20:60

1:3

n=3

1/25000=9/x

x=9×25000

x=225,000km

hope it helps:)

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Solve for d. | - 2d|<10
Romashka-Z-Leto [24]

 Your question: Find D in | - 2d|<10

==========================================================

SOLVING....

Solve the absolute value

|−2d| < 10

     =

−2d < 10

    or

−2d > −10

Solve −2d < 10 for D

Divide each side by -2

-2d ÷ -2 < 10 ÷ -2

d > -5

Now Solve −2d > −10

Divide each side by -2

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Answer: 4 Cups

I think in order to solve this, you would need to add up the fractions that they used. So it would be,

\frac{1}{4}+\frac{1}{4}+\frac{3}{8}+\frac{3}{8}+\frac{5}{8}+\frac{5}{8}+\frac{5}{8}+\frac{7}{8}   Transform the Expressions

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David found and factored out the GCF of the polynomial 80b4 – 32b2c3 + 48b4c. His work is below. GFC of 80, 32, and 48: 16 GCF o
BlackZzzverrR [31]

Answer: The correct statements are

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

David applied the distributive property.

Step-by-step explanation:

GCF = Greatest common factor

1) GCF of coefficients : (80,32,48)

80 = 2 × 2 × 2 × 2 × 5

32 = 2 × 2 × 2 × 2 × 2

48 = 2 × 2 × 2 × 2 × 3

GCF of coefficients : (80,32,48) is 16.

2) GCF of variables :(b^4,b^2,b^4)

b^4= b × b × b × b

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GCF of variables :(b^4,b^2,b^4) is b^2

3) GCF of c^3 and c: c is not the GCF of the polynomial. The variable c is not common to all terms, so a power of c should not have been factored out.

4) 80b^4-32b^2c^3+48b^4c

=16b^2(5b^2-2c^3+3b^2c)

David applied the distributive property.

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