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Burka [1]
3 years ago
7

An auto dealership wants to know the average amount of money its customers can spend on a car. The dealership surveys 50 random

customers and finds that 25 shoppers can spend $10,000 or less, 15 can spend $10,001 to $25,000, and 10 can spend more than $25,000. If 1000 customers visit the dealership this coming weekend, the dealership can estimate that _____ of its customers will have a budget greater than $25,000.
Enter your answer as a number, like this: 42
Mathematics
2 answers:
slega [8]3 years ago
7 0

Answer:

200

Step-by-step explanation:

Given:The dealership surveys 50 random customers and finds that 25 shoppers can spend $10,000 or less, 15 can spend $10,001 to $25,000, and 10 can spend more than $25,000.

To Find:  If 1000 customers visit the dealership this coming weekend, the number of customers having budget greater than $25000.

Solution:

Total Number of surveyed customers=50

The Number of customers that can spend \$ 10000=25

The Number of customers that can spend \$ 10001 to \$ 25000=15

The Number of customers that can spend more than \$ 25000=10

Percentage of people that can spend more than \$ 25000 = Number of customers that can spend more than \$ 25000\setminus Total Surveyed Customers

                                    \left ( 10\setminus 50 \right )\times 100=20%

If 1000 customers visits the dealership,

customer that have budget greater than [\$ 25000= total visiting customers\times percentage of people that can spend more than \$ 25000

                                    1000\times 20\setminus 100

                                    200

Hence the customers that having budget greater than \$ 25000 will be 200

KonstantinChe [14]3 years ago
6 0

Hi I would have to say 350

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One warehouse had 185 tons of coal, another one had 237 tons. The first warehouse delivered 15 tons of coal to its clients daily
lianna [129]

Answer:

In 9 days will the second warehouse have 1.5 times more coal than the first one

Step-by-step explanation:

The coal left in warehouses after x days can be found using the equation:

  • first warehouse: 185 - 15x
  • second warehouse= 237-18x

Let the second warehouse have 1.5 times more coal than the first one after n days then  

  1. 1.5 ×(185 - 15n)=237-18n  which gives:
  2. 277,5-22,5n=237-18n and
  3. 40,5=4,5n
  4. 9=n

7 0
3 years ago
What is the length of the missing leg
Shtirlitz [24]

Answer:

12

Step-by-step explanation:

Using the pythagorean theorem, we know that a^2+ b^2=c^2

In our case, we know b, which is 5 and c which is 13.

If we plug that into the equation, we get a^2+ 5^2 = 13^2

Next, we simplify the equation. a^2 + 25 = 169

Then we subtract 25 from 169. 169 - 25 = 144.

Lastly, we do the square root of 144 and we get 12 which is the missing side.

7 0
3 years ago
Read 2 more answers
What 2 numbers multiply to -100 and add to -21 ​
mylen [45]

Answer:

-25 and 4

Step-by-step explanation:

-25×4=-100 and -25+4=-21

6 0
3 years ago
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UNA POBLACION DE CIERTA CIUDAD EN EL AÑO 2000 ERA DE 250,000 HABITANTES CON UNA TASA DE CRECIMIENTO RELATIVO DEL 2% , DETERMINA
Fofino [41]

Answer:

La población que se espera para el 2012, es 317,060

Step-by-step explanation:

Si la población tiene un crecimiento relativo del 2%, entonces cada año, la población es un 2% más grande que el año anterior.

Definamos P(t) = población después de t años

Entonces, si al año t = 0 (que corresponde con el año 2000) la población es A

P(0) = A

Un año después, en t = 1, la población incrementa en un 2%

P(1) = A + (2%/100%)*A = A + (0.02)*A = A*(1.02)

Otro año después, en t = 2, la población incrementa un 2% de vuelta.

P(2) = A*(1.02) + (2%/100%)*A(1.02) = A*(1.02) + 0.02*A*(1.02)

      = A*(1.02)*(1.02) = A*(1.02)^2

Ya podemos notar un patrón, la población en el año t va a ser:

P(t) = A*(1.02)^t

Sabemos que en t = 0 (el año 2000) la población es 250,000

Entonces A = 250,000

P(t) = 250,000*(1.02)^t

Ahora queremos calcular la población en el año 2012

entonces si t = 0 es el 2000

2012 esta representado con t = 12

Reemplazando eso en la ecuación, obtenemos:

P(12) = 250,000*(1.02)^12 = 317,060.4

Como esto es una población tenemos que redondearlo al próximo número entero, como el primer digito después del punto es 4, redondeamos para abajo.

Entonces la población que se espera para el 2012 es: 317,060

5 0
3 years ago
Find the mean median mode of 12,25,23,17,23
lilavasa [31]
12,17,23,23,25
mod = 23
median = 23
 
4 0
3 years ago
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