Ask question

Ask question

All categories

3 years ago

12

A coin is fixed so that the probability to get heads in two throws is double the probability. Count the probability that there w

ill be head after the second throw.

1 answer:

Setler [38]3 years ago

5 0

Answer:

no clue try looking it up on here see what you find

Step-by-step explanation:

i just wanna help but im not very smart

You might be interested in

Which set of numbers could represent the lengths of the sides of a right triangle?

DiKsa [7]

Answer:

The first set: 8, 15, and 17.

Step-by-step explanation:

<h3>Pair: 8, 15, 17</h3>

By the pythagorean theorem, a triangle is a right triangle if and only if

$\text{longest side}^2 = \text{first shorter side}^2 + \text{second shorter side}^2$ .

In this case,

$\text{longest side}^2 = 17^2 = 289$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 8^2 + 15^2\\ &=64 + 225 = 289 \end{aligned}$ .

In other words, indeed $\text{hypotenuse}^2 = \text{first leg}^2 + \text{second leg}^2$ . Hence, 8, 15, 17 does form a right triangle.

Similarly, check the other pairs. Keep in mind that the square of the longest side should be equal to the sum of the square of the two

<h3>Pair: 10, 15, 20</h3>

Factor out the common factor $2$ to simplify the calculations.

$\text{longest side}^2 = 20^2 = 400$

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 10^2 + 15^2\\ &=100 + 225 = 325 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 12, 18, 22</h3>

$\text{longest side}^2 = (2\times 11)^2 = 2^2 \times 121$ .

$\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= (2 \times 6)^2 + (2 \times 9)^2\\ &=2^2 \times(36 + 81) = 2^2 \times 117 \end{aligned}$ .

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

<h3>Pair: 7, 9, 11</h3>

$\text{longest side}^2 = 11^2 = 121$ .

<h3> $\begin{aligned}&\text{first shortest side}^2 + \text{second shortest side}^2 \\ &= 7^2 + 9^2\\ &=49+ 81 = 130 \end{aligned}$ .</h3>

$\text{longest side}^2 \ne \text{first shorter side}^2 + \text{second shorter side}^2$ .

Hence, by the pythagorean theorem, these three sides don't form a right triangle.

6 0

4 years ago

What is the greatest possible product of a 2 digit number and a 1 digit number?? explain how u know

KIM [24]

To find the greatest possible product, you need the greatest possible numbers. The largest possible 2-digit number is 99. The largest possible 1-digit number is 9. Therefore, 99 * 9 will be the largest possible product under these circumstances.

99 * 9 = 891

Hope this helps! :)

4 0

3 years ago

Determine the period of each function. <br><br> Show Work plzzz

suter [353]

For determining the period of a function, you pick two recognizable tops of the graph and calculate the time difference between them. In this situation the period is 5-1=4, by picking the first two tops

7 0

2 years ago

FInd the distance between the points (9,3) and (1,9)

BARSIC [14]

Answer:

=10

Step-by-step explanation:

1: Add the numbers

2: Factor the numbers

3: Apply radical rule

Answer: =10

<u><em>Hope this helps.</em></u>

3 0

3 years ago

(а+2)(3а-1)<br> what’s the product? (i completely didnt pay attention throughout the year)

Brut [27]

3a^2+5a-2. Hihihihihihi

8 0

3 years ago

Read 2 more answers