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3 years ago

What is the greatest possible product of a 2 digit number and a 1 digit number?? explain how u know

1 answer:

4 0

To find the greatest possible product, you need the greatest possible numbers. The largest possible 2-digit number is 99. The largest possible 1-digit number is 9. Therefore, 99 * 9 will be the largest possible product under these circumstances.

99 * 9 = 891

Hope this helps! :)

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for a certain company, the cost function for producing x items is C(x)=40x+150 and the revenue function for selling x items is R

Mademuasel [1]

Answer :

Step-by-step explaation:

c(80) =40x80 +150 =3350 üretim için 80 parçanın maliyeti

satış için ise : R(80) 0.5(80-110)^2+6,050 = 456

3350-456=2983.95 kar ederler

5 0

2 years ago

Anyone know the answer to this ??

gladu [14]

distribution (if we are talking about algebraic properties)

5 0

3 years ago

Point A is the midpoint of side XZ and point B is the midpoint of side YZ. Triangle X Y Z is cut by line segment A B. Point A is

AveGali [126]

Answer:

<h3>B. 4units</h3>

Step-by-step explanation:

Find the diagram attached. The diagram is a similar triangle.

From the diagram, XZ/XY = CA/AB

Given XZ = 2x-2+2x-2 = 4x-4

XY =5x-7

CA = 2x-2

AB= x+1

On substituting this parameters into the formula to get x first

4x-4/5x-7 = 2x-2/x+1

cross multiply

(4x-4)(x+1) = 5x-7(2x-2)

open the parenthesis

4x²+4x-4x-4 = 10x²-10x-14x+14

4x²-4 = 10x²-24x+14

10x²-4x²-24x+14+4 = 0

6x²-24x+18 = 0

x²-4x+3 = 0

x²-3x-x+3 = 0

x(x-3)-1(x-3) =0

(x-3)(x-1) = 0

x = 3 and 1

Next is to get length AX.

Given AX = 2x-2

Substitute x = 3 into the expression

AX = 2(3)-2

AX = 6-2

AX = 4 units

Hence the measure of length AX is 4 units

4 0

2 years ago

4x2 + x-7 + x2 + 6x + 17 <br><br>what the process in this exercise

inn [45]

Answer:8+x-7+8x+17

9x=18

X=2

Step-by-step explanation:

6 0

3 years ago

Find the missing value when given the modulus. <br><br> |48+bi|=50

xxMikexx [17]

Answer:

missing value b is 14

Step-by-step explanation:

We have been given the modulus of a complex number which is

$r=\sqrt{a^2+b^2}$

Here on comparing the given complex number with general a+bi we get:

a=48 and b=b

On substituting the values in the formula for modulus we get:

$\sqrt{48^2+b^2}=50$

$\Rightarrow 2304+b^2=50^2$

$\Rightarrow b^2=2500-2304$

$\Rightarrow b^2=196$

$\Rightarrow b=\sqrt{196}$

$\Rightarrow b=14$

Therefore, missing value b is 14

4 0

3 years ago