All categories

2 years ago

Which graph represents the solution set of this inequality? -3b - 15 > -24

Mathematics

2 answers:

s2008m [1.1K]2 years ago

8 0

Answer:

Step-by-step explanation:

Natasha2012 [34]2 years ago

3 0

Answer:

REASON:

It's not B or D because it's increasing and it's not C because if -3 - 15 is -18 then I am pretty sure it's not going to be 3 because it's multiplying

You might be interested in

The point (-2, -1) satisfies which of the following inequalities?

satela [25.4K]

Answer:

Step-by-step explanation:

4 0

3 years ago

Easy question Give a formula used for finding the area of a square. Then use the formula to find the area of a square with a sid

Alik [6]

A=s^2

A=6.3^2

(A=6.3x6.3)

And your answer would be:

A=39.69cm^2

4 0

3 years ago

The x-coordinate of the point (50, 55) is ___________.

marysya [2.9K]

The x-coordinate of the point (50, 55) is 50

<h3>What is graph?</h3>

A graph can be defined as a pictorial representation or a diagram that represents data or values.

The distance of point (50, 55) perpendicular to y-axis

Thus, perpendicular distance = 50 units

The x-coordinate of the point (50, 55) is 50

Learn more about graph

brainly.com/question/16608196

#SPJ2

8 0

2 years ago

Read 2 more answers

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .