I don't get it. Can you also explain why and the steps
1 answer:
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$ 1850 was invested in 9% account
<u>Solution:</u>
Given that
Total amount invested by man in two saving accounts = $9493
Simple interest on one account =9%
Simple interest on second account = 10%
Total interest earned = $930.80
Need to determine amount invested in 9 % account.
Let assume amount invested in account where Simple Interest is 9% = x
And assume amount invested in account where Simple Interest is 10% = y
As total amount invested in two accounts is $9493
=> x + y = 9493
=> y = 9493 - x ------(1)
As total interest earned = $930.80
On substituting value of y from equation(1) in above equation , we get
9x + 10 (9493 – x) = 93080
=> 9x + 94930 – 10x = 93080
=> -x = 93080 – 94930
=> -x = -1850
=> x = 1850
Amount invested in account where Simple Interest is 9% = x = $1850
Hence $1850 was invested in 9% account.
Answer (<u>assuming it can be in slope-intercept form)</u>:
y = -x - 1
Step-by-step explanation:
When knowing the slope of a line and its y-intercept, you can write an equation to represent it in slope-intercept form, or y = mx + b format. Substitute the m and b for real values.
1) First, find the slope of the equation, or m. Pick any two points from the line and substitute their x and y values into the slope formula, . I chose the points (0, -1) and (-1, 0):
Thus, the slope is -1.
2) Now, find the y-intercept, or b. The y-intercept of a line is the point at which the line crosses the y-axis. By reading the graph, we can see that the line intersects the y-axis at the point (0,-1), therefore that must be the y-intercept.
3) Now, substitute the found values into the y = mx + b formula. Substitute -1 for m and -1 for b: