Answer:
In first equation if we put the value of x and y (x=2,y=2)than,
3x+y=8
3×x+y=8
3×2+2=8
6+2=8
8=8
in second equation the value of x=2,y=1
x2+xy=6
x2+x×y=6
4+2×1=6
4+2=6
6=6
Let r, g and b represent red, green and blue.
r+g+b = 74
r=g-1
b=r+g
Again, r+g+b = 74. Let's substitutte r+g for b: r+g+(r+g) = 74.
Next, let's eliminate r. Use r=g-1. Then g-1 + g + g-1 + g = 74
Combining the g terms, 4g - 2 = 74 => 4g = 76 => g = 19
Recall that r=g-1
and
b=r+g
Find r. If r=g-1, and g=19, then r = 19-1=18
Find b: b = r+g = 18+19=37
So there are 37 blue candies, 18 red candies and 19 green candies.
Check: 37+18+19=74 ??? Yes.
I see your last line is : c(x) = 0.9(x^2-10)^2 + 101.1
Let y = x^2, then c(y) = 0.9(y-10)^2 + 101.1
Apparently, c(y) is a parabola, min is 101.1 when y = 10, max is infinity
So let x^2 = 10 -> x = sqrt(10) or -sqrt(10), min is 101.1, max is infinity
Answer:
Neither.
Step-by-step explanation:
I am not completely sure, so make sure to also let other answer this before you trust me lol. I really hope this helps!!
let the numbers are x , x+1 ,x+2
∴ 6 [ x + (x+1) +(x+2) ] = 162
∴ x + (x+1) + (x+2) = 162/6 = 27
∴3x + 3 = 27
∴ 3x = 27 - 3 = 24
∴ x = 24/3 = 8
<u>So, the numbers are 8 , 9 , 10</u>
