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3 years ago

PLEASE HELP. i have been working on this for an hour!!!

Mathematics

1 answer:

Dima020 [189]3 years ago

8 0

Answer:

AB = 133m

Step-by-step explanation:

You can notice the ratio of AE to DE is the same as the ratio from BE to CE(3.5). We can also say angle AEB is congruent to angle DEC because they are vertical angles. Now, because of SAS similarity, you can say triangle AEB and DEC are similar. We can set up these proportions from the definition of similar triangles:

DE / AE = BE / CE = DC / AB

And we can plug in the values we have:

42 / 147 = 36 / 126 = 38 / AB

2 / 7 = 2 / 7 = 38 / AB

We can cross-multiply to get:

2AB = 7 * 38

2AB = 266

AB = 133 m

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Answer:

x=5

Step-by-step explanation:

(5x+2)/3 = 9

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3 years ago

Hanson has 38 pieces of candy. He gives away c of the pieces. Write an expression that

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Answer:

38-c

Step-by-step explanation:

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4 years ago

What is 2384598 increased by six million

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3 years ago

Lieutenant Commander Data is planning to make his monthly (every 30 days) trek to Gamma Hydra City to pick up a supply of isolin

Nookie1986 [14]

Answer:

$N = 209 \ unites$

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Step-by-step explanation:

From the question we are told that

The daily demand is $d = 7/day$

The standard deviation is $\sigma = 3 /day$

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The number of days in his monthly is $T = 30 \ days$

The lead time is $L = 4$

Generally the number he should order (optimal order ) is mathematically represented as

$N = d(L + T)+(\sigma_{T + L} * z) -k$

Here $\sigma__{T+L }}$ is the monthly standard deviation which is mathematically evaluated as

$\sigma__{T + L}} = \sqrt{(T + L) * 1^2}$

=> $\sigma__{T + L}} = \sqrt{34}$

=> $\sigma__{T+L}} = 5.83$

Also z-value for the 95% service probability from the z-table is 1.96

$N = 7 * (30 +4 ) + (1.96 * 5.83) - 40$

=> $N = 209 \ unites$

For the maximum order quantity k = 0

$N_{max} = d(L + T)+(\sigma_{T + L} * z) -0$

=> $N_{max} = 7 * (30 +4 ) + (1.96 * 5.83) - 0$

=> $N_{max} = 249$

7 0

3 years ago

A chemist has two large containers of sulfuric acid solution, with different concentrations of acid in each container. Blending

erma4kov [3.2K]

A is the concentration of the first container, B the second container.

300a+600b=900·(15)=13500
1.3a+6b=135

100a+500b=600·(12.5)=7500
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Multiply eq. 2 by (-3) and add to eq. 1 to eliminate A.
3a+6b-3a-15b=135-225
-9b=-90
b=10
Then from eq. 2,
a+50=75
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The first container is a 25% solution and the second container is a 10% solution

5 0

3 years ago