Answer:
1.9 feets (nearest tenth) ;
24.9 feets
Step-by-step explanation:
Given that :
Angle, θ = 4.3°
Length of ramp = 25
Maximum Height, h ;
sinθ = opposite / hypotenus
Sin 4.3 = h / 25
0.0749787 * 25 = h
1.874 feet = h
1.9 feets (nearest tenth)
Distance along the ground the ramp could cover :
Cos θ = Adjacent / hypotenus
Cos 4.3 = x / 25
0.9971851 = x / 25
0.9971851 * 25 = x
x = 24.929
x = 24.9 (nearest tenth)
49.686 kg
Since the density of the air remains constant in the question
We can represent this equation as a ratio;
10 m³ = 13 kg
(4.2 * 3.5 * 2.6) m³ = ? (x) kg
4.2 * 3.5 * 2.6 = 38.22
We cross multiply
38.22 * 13 = 10 * x
X = 496.86 /10
X = 49.686
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1 and 2/3 or 5/3