That system has D. no solutions
ANSWER:
x=4 and y= -1
Explanation:
Add these equations to eliminate y:
4x=6
Then solve 4x =16 for x:
4x=16
4x/4 = 16/4 (divide both sides by 4)
x=4
Now that we have found x lets plug it back in to solve for y.
Write down an original equation:
x-3y=7
Substitute 4 for x-3y=7:
4-3y=7
-3y+4=7 (simplify both sides of the equation)
-3y+4+ (-4) = 7+ (-4) (add -4 to both sides of the equation)
-3y = 3
-3y/-3 = 3/-3 (Divide both sides by -3)
y= -1
I HOPE THIS HELPS
Volume of Cylinder V = πr²h
diameter = 6 feet, radius = 6/2 = 3 feet
dV/dt = (dV/dh) * (dh/dt) by change rule.
V = <span>πr²h
dV/dh = </span>πr² = π*3² = 9π ft²<span>
dV/dt = 2 ft</span>³/min
<span>dV/dt = (dV/dh) * (dh/dt)
</span>
2 ft³/min = 9π ft² * (dh/dt)
9π ft² * (dh/dt) = 2 ft<span>³/min
</span>
(dh/dt) = (2 ft³/min)/(9π ft<span>²)
(dh/dt) = (2/</span>9π) ft/min
So the water level is rising at (2/9<span>π) ft/min.</span>
The value would 223. all that needs to be done is substitute 6 for a and 3 for b.
That's also known as the addition method.
x + y = 40
.08x+.03y=1.7
We need to multiply the top equation by either a -.08 or a -.03 to eliminate one of the variables. Let's get rid of the y:
-.03(x + y) = -.03(40) which gives us
-.03x - .03y = -1.2
.08x + .03y = 1.7
When we add those together we are left with .05x = .5 and x = 10. If we sub that 10 in for x into the first equation (either would have worked but the first one is way easier to work with!) we get 10 + y = 40 and y = 30. So the solution to the system is (10, 30)
