Round to the nearest tenth (IXL Pythagorean theorem)
1 answer:
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<em>Note: You may have missed to add the dot plots chart, so I found the chart after a little research and hence, I am attaching it and based on that dot plot chart I am solving the question which anyways would clear you concept.</em>
Answer:
''The median for the students is 2 and the median for the teachers is 3'' is the right option which compares the medians of the data.
Step-by-step explanation:
Data for students from the dot plot in order
Calculating Median for students:
0, 0, 1, 1, 1, 1, 2, 2, 2, 2, 2, 2, 2, 3, 3, 3, 3, 3, 4, 4
As you can see, we do not have just one middle number but we have a pair of middle numbers i.e. 2 and 2, so the median is the average of these two numbers:
Median = (2+2)/2
=4/2
= 2
Data for teachers from the dot plot in order
Calculating Median for teachers:
0, 1, 1, 1, 2, 2, 3, 3, 3, 3, 3, 4, 4, 4, 4, 5, 5, 5, 6, 8
As you can see, we do not have just one middle number but we have a pair of middle numbers i.e. 3 and 3, so the median is the average of these two numbers:
Median = (3+3)/2
=6/2
= 3
Therefore, ''the median for the students is 2 and the median for the teachers is 3'' is the right option which compares the medians of the data.
Answer:
the two roots are x = 1 and x = 4
Step-by-step explanation:
Data provided in the question:
(x³ − 64) (x⁵ − 1) = 0.
Now,
for the above relation to be true the following condition must be followed:
Either (x³ − 64) = 0 ............(1)
or
(x⁵ − 1) = 0 ..........(2)
Therefore,
considering the first equation, we have
(x³ − 64) = 0
adding 64 both sides, we get
x³ − 64 + 64 = 0 + 64
or
x³ = 64
taking the cube root both the sides, we have
∛x³ = ∛64
or
x = ∛(4 × 4 × 4)
or
x = 4
similarly considering the equation (2) , we have
(x⁵ − 1) = 0
adding the number 1 both the sides, we get
x⁵ − 1 + 1 = 0 + 1
or
x⁵ = 1
taking the fifth root both the sides, we get
also,
1 can be written as 1⁵
therefore,
or
x = 1
Hence,
the two roots are x = 1 and x = 4