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Aliun [14]
3 years ago
10

PLZ HELP PLZ HELP The histogram below shows the homework grades from the last assignment in Mr. Smith's class.

Mathematics
1 answer:
KonstantinChe [14]3 years ago
4 0

Answer:

Median, Interquartile range

Step-by-step explanation:

I took the test.

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A sample of 1000 college students at NC State University were randomly selected for a survey. Among the survey participants, 102
cupoosta [38]

Answer:

The upper endpoint of the 99% confidence interval for population proportion is 0.13.

Step-by-step explanation:

The confidence interval for population proportion is:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}

<u>Given:</u>

<em>n</em> = 1000

\hat p = 0.102

z_{\alpha /2}=z_{0.01/2}=z_{0.005}=2.58

*Use the standard normal table for the critical value.

Compute the 99% confidence interval for population proportion as follows:

CI=\hat p\pm z_{\alpha /2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\=0.102\pm 2.58\times\sqrt{\frac{0.102(1-0.102)}{1000}}\\=0.102\pm0.0248\\=(0.0772, 0.1268)\\\approx (0.08, 0.13)

Thus, the upper limit of the 99% confidence interval for population proportion is 0.13.

6 0
3 years ago
the sum of the distances two hikers walked is 53 miles, and the difference is 25 miles. what are the distances
mestny [16]
To solve this problem, you can create a system of equations and solve for each hiker's distance walked.

Hiker 1 distance walked: x
Hiker 2 distance walked: y

Their combined distance walked is 53 miles, thus - 
x + y = 53

The difference between miles walked is 25, thus - 
x - 25 = y

Let's solve using substitution. To do that, substitute x - 23 into x + y = 53 for y.

x + y = 53
x + (x - 25) = 53
x + x - 25 = 53
2x - 25 = 53
2x = 78
x = 39

To find y, substitute 39 for x into either of the equations.

x + y = 53
39 + y = 53
y = 14

Finally, check all work.

x + y = 53
39 + 14 = 53
53 = 53

x - 25 = y
39 - 25 = 14
14 = 14

Answer:
One hiker walked 39 miles and the other hiker walked 14 miles.
4 0
3 years ago
Is 27 a solution???
Shkiper50 [21]
Solution is 30 for the problem x-20=10
5 0
3 years ago
Which expression is equivalent to sec^2xcot^2x
Dimas [21]

Answer:

B

Step-by-step explanation:

Using the identities

sec x = \frac{1}{cosx} , csc x = \frac{1}{sinx} , cot x = \frac{cosx}{sinx} , then

sec²x cot²x

= \frac{1}{cos^2x} × \frac{cos^2x}{sin^2x} ( cancel out cos²x )

= \frac{1}{sin^2x}

= csc²x → B

8 0
3 years ago
The formula for determining the pressure, p, exerted on an object at a depth, h, below the surface of a liquid is p = s + dgh, w
Gwar [14]

Answer:

<em>The formula for determining the pressure, p, exerted on an object at a depth, h, below the surface of a liquid is p = s + </em><em>dgh</em>

<em>p(pressure) = s(atmospheric \: pressure) + d(density \: of \: the \: liquid)g(acceleration \: due \: to \: gravity)h</em>

Step-by-step explanation:

<em> where s is the atmospheric pressure, d is the density of the liquid and g is the acceleration due to gravity.</em>

7 0
3 years ago
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