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3 years ago

Can someone help me solve these metric system operations???

Mathematics

1 answer:

Dimas [21]3 years ago

6 0

lDK

but friend me on discord, and follow my robIox account, then we will talk.

discord: datboythomas123#8606

robIox: chexmix1202

HAPPY APRIL FOOLS!! *laughs SUUUUUUUUUUUPERRRRRRRR cutely*

BUT! I will answer...

if u friend me on discord, and follow my robIox account, then we will talk.

discord: datboythomas123#8606

robIox: chexmix1202

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there are 28 tables in the cafeteria.each table has 12 students sitting at it.fourth graders sit at 13 of the yables.fifth grade

Darya [45]

Hope this helps!

28 - 13 = 15
15 x 12 = 180 Fifth graders

6 0

3 years ago

Help<br> Me ? I’m marking brainlist

dsp73

Answer: I belive the answer is C

Step-by-step explanation:

7 0

2 years ago

A blackjack is a 10-point card and an ace for a value of 21. Use your answers to parts (a), (b), and (c) to determine the probab

kondor19780726 [428]

Answer:

Results:

0.1432

0.0045

0.0905

0.0483

Step-by-step explanation:

Step a:

P(A or 10, A or 10) = 20/52 * 19/51 = 5/13 / 19/51 = 95/663 = 0.1432

Step b:

P(A A) = 4/52 * 3/51 = 1/13 * 1/17 = 1/221 = 0.0045

Step c:

P(10 10) = 16/52 * 15/51 = 4/13 * 5/17 = 20/221 = 0.0905

Step d:

P(A 10 or 10 A) = 2 * 4/52 * 16/51 = 2/13 * 16/51 = 32/663 = 0.0483

As well we get the probability by subtracting a, b and c:

P(blackjack): 0.1432 - 0.0905 - 0.0045 = 0.0482

7 0

3 years ago

Solve: 0.2c + 0.69 = 1.37 c = _____

iVinArrow [24]

Answer:

c = 3.4. I hope this is the answer:)

5 0

3 years ago

Lizzie has 30 coins that total $4.80. All of her coins are dimes, D, and quarters, Q. Algebraically determine how many of each t

Gnom [1K]

Lizzie has 18 dimes and 12 quarters

<em><u>Solution:</u></em>

Let "d" be the number of dimes

Let "q" be the number of quarters

We know that,

value of 1 dime = $ 0.10

value of 1 quarter = $ 0.25

Given that LIzzie has 30 coins

number of dimes + number of quarters = 30

d + q = 30 ---- eqn 1

Also given that the coins total $ 4.80

number of dimes x value of 1 dime + number of quarters x value of 1 quarter = 4.80

$d \times 0.10 + q \times 0.25 = 4.80$

0.1d + 0.25q = 4.8 ------ eqn 2

Let us solve eqn 1 and eqn 2

From eqn 1,

d = 30 - q ---- eqn 3

Substitute eqn 3 in eqn 2

0.1(30 - q) + 0.25q = 4.8

3 - 0.1q + 0.25q = 4.8

0.15q = 1.8

From eqn 3,

d = 30 - 12

Thus she has 18 dimes and 12 quarters

6 0

3 years ago