At Venn diagram there are 4 parts (20 pieces):
1. Colored only in blue - quadrilaterals with four equal side lengths (3 pieces);
2. Colored only in orange - quadrilaterals with four right angles (6 pieces);
3. Colored in both blue and orange - quadrilaterals with four right angles and with four equal side lengths (2 pieces);
4. Colored in white - quadrilaterals withoutprevious two properties (9 pieces).
Consider events:
A - a randomly chosen quadrilateral has four right angles;
B - a randomly chosen quadrilateral has four equal side lengths;
Use formula
to find the probability that a randomly selected quadrilateral with 4 right angles also has four equal side lengths:

Answer: Pr=0.25
Answer:
The expected value for the insurance company is $200
Step-by-step explanation:
In order to calculate the expected value for the insurance company we would have to make the following calculation:
expected value for the insurance company=expected value live+expected value die
expected value live=Net gain*probability of living
expected value live=$300*0.999=$299.70
expected value die=Net gain*probability of die
expected value die=(-$100,000 + $300)*0.001
expected value die=$-99.70
Therefore, expected value for the insurance company=$299.70-$99.70
expected value for the insurance company=$200
The expected value for the insurance company is $200
Answer:
-3x - 2y + 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
3 + 5x - 4y + 2y - 8x
<u>Step 2: Simplify</u>
- Combine like terms (x): -3x - 4y + 2y + 3
- Combine like terms (y): -3x - 2y + 3
The 3rd option is correct
Answer:
5x + 2x.....combine like terms..... = 7x
5x + 2x....subbing in 1 7x - 1....subbing in 1
5(1) + 2(1) = 5 + 2 = 7 7(1) - 1 = 7 - 1 = 6
5x + 2x...subbing in 2 7x - 1...subbing in 2
5(2) + 2(2) = 10 + 4 = 14 7(2) - 1 = 14 - 1 = 13
5x + 2x...subbing in 3 7x - 1...subbing in 3
5(3) + 2(3) = 15 + 6 = 21 7(3) - 1 = 21 - 1 = 20
5x + 2x...subbing in 4 7x - 1....subbing in 4
5(4) + 2(4) = 20 + 8 = 28 7(4) - 1 = 28 - 1 = 27
5x + 2x...subbing in 5 7x - 1...subbing in 5
5(5) + 2(5) = 25 + 10 = 35 7(5) - 1 = 35 - 1 = 34
5x + 2x result values are 1 more then 7x - 1 result values
there are no values that will make the 2 expressions equal....
because 5x + 2x = 7x......and the other one is 7x - 1......so the 7x - 1 values will always be 1 number less...because ur subtracting one
Step-by-step explanation: