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aliina [53]
3 years ago
12

Principle of rocket propulsion is based on _​

Computers and Technology
1 answer:
GalinKa [24]3 years ago
4 0
Answer: Newton’s third law of motion
Explanation: The propulsion of all rockets, jet engines, deflating balloons, and even squids and octopuses is explained by the same physical principle—Newton's third law of motion.
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CHOOSE THE CORRECT CONTINUOUS TENSES( PRESENT CONTINUOUS,PAST CONTINUOUS AND FUTURE CONTINUOUS) : 1. I saw a snake while I _____
k0ka [10]

Answer:

Explanation:

joe biden>

7 0
3 years ago
Prove each statement using a proof by exhaustion. For every integer n such that 0 lessthanorequalto n < 3, (n + 1)^2 > n^3
yawa3891 [41]

Answer:

See attachment below

Explanation:

5 0
3 years ago
2) [13 points] You’ve been hired by Banker Bisons to write a C++ console application that determines the number of months to rep
Paha777 [63]

Answer:

Check the explanation

Explanation:

CODE:

#include <iostream>

#include <iomanip>

using namespace std;

double getLoanAmount() { // functions as per asked in question

double loan;

while(true){ // while loop is used to re prompt

cout << "Enter the car loan amount ($2,500-7,500): ";

cin >> loan;

if (loan>=2500 && loan <= 7500){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< loan << " is an invalid loan amount." << endl;

}

}

return loan;

}

double getMonthlyPayment(){ // functions as per asked in question

double monthpay;

while(true){ // while loop is used to re prompt

cout << "Enter the monthly payment ($50-750): ";

cin >> monthpay;

if (monthpay>=50 && monthpay <= 750){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: $"<< monthpay << " is an invalid monthly payment." << endl;

}

}

return monthpay;

}

double getInterestRate(){ // functions as per asked in question

double rate;

while(true){ // while loop is used to re prompt

cout << "Enter the annual interest rate (1-6%): ";

cin >> rate;

if (rate>=1 && rate <= 6){ // if the condition is fulfilled then

break; // break statement is use to come out of while loop

}

else{ // else error message is printed

cout << "Error: "<< rate << "% is an invalid annual interest rate." << endl;

}

}

return rate;

}

int main() {

cout << setprecision(2) << fixed; // to print with 2 decimal places

int month = 0; // initializing month

// calling functions and storing the returned value

double balance= getLoanAmount();

double payment= getMonthlyPayment();

double rate= getInterestRate();

rate = rate /12 /100; // as per question

// printing as per required in question

cout << "Month Balance($) Payment($) Interest($) Principal($)"<< endl;

while(balance>0){ // while the balance is more than zero

month = month + 1; // counting Months

// calculations as per questions

double interest = balance * rate;

double principal = payment - interest;

balance = balance - principal;

// printing required info with proper spacing

cout <<" "<< month;

cout <<" "<< balance;

cout <<" "<< payment;

cout <<" "<< interest;

cout <<" "<< principal << endl;

}

cout << "Months to repay loan: " << month << endl; // displaying month

cout << "End of Banker Bisons";

Kindly check the output in the attached image below.

5 0
3 years ago
Which access control principle limits a user's access to the specific information required to perform the currently assigned tas
Svetradugi [14.3K]

Answer:

The answer is "Need-To-Know Access Control Principle"

Explanation:

There are three types of access control methods such as Role-Based Access Control, Discretionary Access Control and Mandatory Access Control.

The access control principle that limits/blocks the user from gaining access to a folder/information/procedure within the system is called "Need-To-Know Access Control Principle".

I hope this answer helps.

4 0
3 years ago
Write a program that prompts the user to input a number. The program should then output the number and a message saying whether
Gala2k [10]

Answer:

Following is the program in C++ Language

#include <iostream> // header file

using namespace std; // namespace std

int main() // main method

{

   int n;  // variable declaration

   cout<<" Please enter the number :";

   cin>>n; // Read the number

   if(n>0) // check the condition when number is positive

   {

cout<<n<<endl<<"The number is Positive"; // Display number

   }

  else if(n<0) // check the condition when number is Negative

  {

cout<<n<<endl<<"The number is Negative";// Display number

  }

  else // check the condition when number is Zero

  {

cout<<n<<endl<<"The number is Zero";// Display number

  }

   return 0;

  }

Output:

Please enter the number:

64

The number is Positive

Explanation:

Following are the description of the program

  • Declared a variable "n" of int type.
  • Read the value of "n" by user.
  • Check the condition of positive number by using if block statement .If n>0 it print the number is positive.
  • Check the condition of negative number by using else if block statement If n<0 it print the number is negative.
  • Finally if both the above condition is fail it print the message " The number is Zero"

7 0
3 years ago
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