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ANEK [815]
4 years ago
14

Please help!! I’m very confused and tried everything:(

Mathematics
2 answers:
erastovalidia [21]4 years ago
4 0

Answer:

the answer is 300 if you divide y'know

Step-by-step explanation:

Lorico [155]4 years ago
4 0

Answer:

Look down

Step-by-step explanation:

by the 30-60-90 rule the 10 is the middle side so the shortest side is 10*1/sqrt(3) of that and the longest side is double of that.

the answer is \frac{20}\sqrt{3}

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1. The area of a circle is 60 square units. What is the area of ...
amid [387]

Answer:

30

Step-by-step explanation:

60=whole

60/2=30

8 0
3 years ago
Help PLS ILL GIVE BRAINLIEST FOR CORRECT ANSWER
Licemer1 [7]
The answer is D ! U just have to see the numbers the left corner
3 0
3 years ago
I have multiple questions:<br> 1: 2/3÷4/5<br> 2: 2 1/9÷2/3<br> 3: 3/5÷1 1/4
Setler79 [48]

Answer:

1: 5/6

2: 3 1/6

3: 12/25

hope this helps!!

p.s

    comment if wrong

8 0
4 years ago
5(x+3)can you tell me please
-BARSIC- [3]
What you do is you distribute the 5.

So your answer would be 5x+15
5 0
3 years ago
Read 2 more answers
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
4 years ago
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