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castortr0y [4]
3 years ago
9

Kite ABCD is reflected over the line y = x. What rule shows the input and output of the reflection, and what is the new coordina

te of A'?
(x,y)→(y,x); A' is at (2, −7)
(x,y)→(−x,y); A' is at (7, 2)
(x,y)→(−x,−y); A' is at (7, −2)
(x,y)→(y,−x); A' is at (2, 7)
Mathematics
2 answers:
jeyben [28]3 years ago
7 0

Answer:

(x,y)→(y,x); A' is at (2, −7)

Step-by-step explanation:

Svetach [21]3 years ago
4 0
The answer:

according to the image the coordinates of pre image are:

A(-7, 2), B(-5, 3) C(-2, 2) and D(-5, 1)

<span>Kite ABCD is reflected over the line y = x, the main rule to find the coordinates of the images is  (y, x)

for example if A(-7, 2) the image  A' is A'(2, -7)

the answer is </span><span>(x,y)→(y,x); A' is at (2, −7)</span>
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8 0
3 years ago
A circle representing a pool is graphed with a center at the origin. Grant enters the pool at point A and swims over to a friend
anyanavicka [17]

Answer:

The equation of Grant's path is y = 4 - x over 2 ⇒ 2nd answer

Step-by-step explanation:

The form of the linear equation is y = m x + b, where

  • m is the slope of the line
  • b is the y-intercept (value y at x = 0)

The formula of the slope of a line is m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

∵ Grant's path is a line from point A to point B

∴ The equation of AB represents Grant's path

Lets find the slope of AB using the formula of the slope above

∵ A = (8 , 0)

∵ B = (-4 , 6)

∴ x_{1} = 8 and x_{2} = -4

∴ y_{1} = 0 and y_{2} = 6

∵ m=\frac{6-0}{-4-8}=\frac{6}{-12}

∴ m=-\frac{1}{2}

Substitute the value of m in the form of the equation

∵ y = m x  + b

∴ y = -\frac{1}{2} x + b

∵ b is the value of y at x = 0

∵ y = 4 at x = 0 ⇒ from the figure

∴ b = 4

∴ y = -\frac{1}{2} x + 4

We can write -\frac{1}{2} x as -\frac{x}{2}

∴ y =  -\frac{x}{2} + 4

- Switch the two terms of the right hand side

∴ y = 4 -  \frac{x}{2}

The equation of Grant's path is y = 4 -  \frac{x}{2}

4 0
3 years ago
The length of a rectangle is 6 m longer than its width. If the perimeter of the rectangle is 32 m , find its area.
Hunter-Best [27]
Standard calculation for Perimeter is 2L+2W=P or 2(L+W)=P
As we have the totals for the perimeter at 32m and know the lenght is 6m longer than width we can build an equation to find W.

2(L+W)=Perimeter
2(x+x+6)=32
2(2x+6)=32
2x+6=32/2
2x+6=16
2x=16-6
2x=10
x=10/2
x=5

Now we have the width of 5m.  As length is 6m longer than width means we add 6m to 5m to determine length

L=W+6
L=5+6
L=11

To determine if your calculations are correct place your L and W answers into original eqution to determine perimeter

2(11+5)=32
2(16)=32
32=32

Yes, it is found correct.  Now to find the Area using the standard formula for Area.  Area=L*W or A=LW

A=(11)(5)
A=55

Area = 55sq m

5 0
3 years ago
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