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Oliga [24]
3 years ago
8

How many squares are in this figure in all?

Mathematics
2 answers:
Tanya [424]3 years ago
6 0

Answer:

explanation

Step-by-step explanation:

there

are

22

squares

all

together

Wittaler [7]3 years ago
4 0

There are <u>23</u> Squares within this figure

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1
Blababa [14]

Answer:

76

Step-by-step explanation:

7 0
3 years ago
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Put the following equation in slope-intercept form: y−5=7/4(x-1)
Lelu [443]

Answer:

y - 5 =  \frac{7}{4} (x - 1) \\ 4y - 20 = 7x - 7 \\ 4y = 7x  + 13 \\  y =  \frac{7}{4} x +  \frac{13}{4}

4 0
3 years ago
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The world's largest cookie was baked in North Carolina in 2003. Its diameter was 100 feet and it contained about 6,000 pounds of
Natasha2012 [34]

Answer:

16022 square foot

Step-by-step explanation:

The world's largest cookie was baked in North Carolina in 2003. Its diameter was 100 feet and it contained about 6,000 pounds of chocolate chips! If the cookie was a cylinder 1 foot tall, and you wanted to cover it with icing, how many square inches would you have to ice? Use 3.14 for .

We find the surface area of the cylinder

= 2πr(r + h)

r = Diameter /2 = 100 feet/2

r = 50 feet

h = 1 feet

Hence

2 × 3.14 × 50(50 + 1)

= 16022.122533 square foot

= 16022 square foot

4 0
3 years ago
What are the parents points for the equation f(x) = 3^x?
ryzh [129]

Answer:

(0, 1) and (1, 2)

Step-by-step explanation:

{ \rm{f(x) =  {3}^{x} }}

• Assume f(x) is one

{ \rm{ {3}^{x} = 1}}

• Apply logarithms:

{ \rm{x log(3)  =  log(1) }} \\  \\ { \rm{x = 0 }}

• Assume f(x) is 2

{ \rm{x =  \frac{ log(2) }{ log(3) } }} \\  \\ { \rm{x = 1}}

3 0
2 years ago
Which are the maximum values ? I will add a picture please help
Alik [6]

Answer:

58 at the point (9,8)

7 at the point (1, 1)

Step-by-step explanation:

The maximum points will be found in the vertices of the region.

Therefore the first step to solve the problem is to identify through the graph, the vertices of the figure.

The vertices found are:

(1, 10)

(1, 1)

(9, 5)

(9, 8)

We look for the values of x and y belonging to the region, which maximize the objective function f(x, y) = 2x + 5y. Therefore we look for the vertices with the values of x and y higher.

(1, 10), (9, 5), (9, 8)

Now we substitute these points in the objective function and select the one that produces the highest value for f (x, y)

f(1, 10) = 2(1) + 5(10) = 52\\\\f(9, 5) = 2(9) + 5(5) = 43\\\\f(9, 8) = 2(9) + 5(8) = 58

The point that maximizes the function is:

(9, 8) with f(9, 8) = 58

Then the value that produces the minimum of f(x, y) is (1, 1)

f(1, 1) = 2(1) + 5(1) = 7

5 0
3 years ago
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