If you know that -2 is a zero of f(x) = x^3 + 7x^2 + 4x - 12, explain how to solve the equation.
First you have to figure out what could make f(x) = 0 to get rid of the cube. I'm going to test the array of data, x = -2, x = -3, and x = -4 because this type of equation probably has more negative values given that if you plug in some values the cubed-values and squared-values will surpass the "-12". Plug this into a calculator.
x^3 + 7x^2 + 4x - 12
f(-2) = -8 + 28 - 8 - 12 = 0
So you know that when x = -2, f(x) = 0. Divide "(x + 2)" from the equation and you will get... x^2 + 5x - 6. Now this is a simple polynomial one that you can figure to be (x + 6) (x - 1) just by looking at it because -6 multiplied by 1 is negative 6 and you see 5 and know that 6 - 1 = 5.
The solution is (x + 6) (x - 1) (x + 2) meaning that when x = -6, 1, or -2, f(x) is 0.
Answer:
12−2
Step-by-step explanation:
Simplify,
(11+3)+(−5)
11+3+−5
Subtract,
11+3+−5
11−2+
Combine like terms,
11−2+
12−2
Since we can't go any further, the solution is,
12−2
Answer:
The answer is suppose to be -15.
Step-by-step explanation:
I do not see any statements
I can give you an explanation
Layla forgot to carry the negative
Answer:
5
Step-by-step explanation:
f(-5)=-(-5)^2 - 7(-5) - 5
f(-5)= -25 +35 - 5
f(-5) = -25 +30
f(-5) = 5
Answer:
M
Step-by-step explanation:
The angle bisector is M
