x and y are two integers and x ≠ 0. Which of the following is not a rational number? a) z b) y c)x/y d) y/x

Mathematics

1 answer:

BaLLatris [955]2 years ago

4 0

Answer: Choice A) z

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Explanation:

x and y are two integers, with x being nonzero

This means x/y is rational as long as y is nonzero as well. If y = 0, then we have a division by zero error. Try something like 1/0 on your calculator and you'll find it doesn't work.

Similarly, y/x is rational as well. Any rational number is simply dividing two integers as a fraction like this. Other examples include stuff like 1/2, 4/5, 8/17, and so on.

Since y is an integer, this means we can write it like this: y = y/1. This shows any integer is also rational, but not the other way around. A fraction like 2/3 is rational but not an integer.

All of what was discussed above indicates that choices B, C and D can be ruled out. The only thing left is choice A. The variable z isn't defined, so it's not clear what it is exactly. But it's likely the answer as it's the only thing left after the eliminations.

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2 years ago

Find the 2nd Derivative: f(x) = 3x⁴ + 2x² - 8x + 4

ad-work [718]

Answer:

$f''(x)=36x^2+4$

Step-by-step explanation:

Let's start by finding the first derivative of $f(x)= 3x^4+2x^2-8x+4$ . We can do so by using the power rule for derivatives.

The power rule states that:

$\frac{d}{dx} (x^n) = n \times x^n^-^1$

This means that if you are taking the derivative of a function with powers, you can bring the power down and multiply it with the coefficient, then reduce the power by 1.

Another rule that we need to note is that the derivative of a constant is 0.

Let's apply the power rule to the function f(x).

$\frac{d}{dx} (3x^4+2x^2-8x+4)$

Bring the exponent down and multiply it with the coefficient. Then, reduce the power by 1.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = ((4)3x^4^-^1+(2)2x^2^-^1-(1)8x^1^-^1+(0)4)$

Simplify the equation.

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x^1-8x^0+0)$
$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8(1)+0)$

$\frac{d}{dx} (3x^4+2x^2-8x+4) = (12x^3+4x-8)$
$f'(x)=12x^3+4x-8$

Now, this is only the first derivative of the function f(x). Let's find the second derivative by applying the power rule once again, but this time to the first derivative, f'(x).