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kap26 [50]
3 years ago
13

If 588 digits were used to number the pages of a book how many pages are in this book.

Mathematics
1 answer:
iVinArrow [24]3 years ago
6 0

Answer: 232 pages

Step-by-step explanation:

Total digits = 588

1 digit page number:

1 to 9 = 1 × 9 = 9

Number of pages = 9/1 = 9

2 - digit page number :

10 - 99 = 2 × 90 = 180

Number of pages = 180/2 = 90

3 - digit page number :

588 - (9 + 180) = 588 - 189 = 399

Number of pages with 3 - digits = 399/3 = 133

Therefore, the total number of pages the book has is :

(9 + 90 + 133) = 232 pages

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9514 1404 393

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Step-by-step explanation:

There are several ways you can go at this. Here are 3 of them:

  1. along an extension of the lower right vertical edge, divide the figure into a rectangle and a right triangle.
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Here's what those computations look like:

1. rectangle: 60m wide by 80 m high = 4800 m².

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2. The trapezoid has bases of 80 m and 10 m, and a height of 60 m. Its area is ...

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The (negative) trapezoid at right has bases of 10 m and 80 m, and a width of 190-60 = 130 m. Its area is ...

  A = (1/2)(10 m +80 m)(130 m) = 5850 m²

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