Answer:
∠ACB ≅ ∠AGB
Step-by-step explanation:
AAS Postulate is angle-angle-side, which means that both triangles are congruent if 2 angles and a side are congruent.
We have proven that the trigonometric identity [(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] equals 1 + (secθ * cosec θ)
<h3>How to solve Trigonometric Identities?</h3>
We want to prove the trigonometric identity;
[(tan θ)/(1 - cot θ)] + [(cot θ)/(1 - tan θ)] = 1 + sec θ
The left hand side can be expressed as;
[(tan θ)/(1 - (1/tan θ)] + [(1/tan θ)/(1 - tan θ)]
⇒ [tan²θ/(tanθ - 1)] - [1/(tan θ(tanθ - 1)]
Taking the LCM and multiplying gives;
(tan³θ - 1)/(tanθ(tanθ - 1))
This can also be expressed as;
(tan³θ - 1³)/(tanθ(tanθ - 1))
By expansion of algebra this gives;
[(tanθ - 1)(tan²θ + tanθ.1 + 1²)]/[tanθ(tanθ(tanθ - 1))]
Solving Further gives;
(sec²θ + tanθ)/tanθ
⇒ sec²θ * cotθ + 1
⇒ (1/cos²θ * cos θ/sin θ) + 1
⇒ (1/cos θ * 1/sin θ) + 1
⇒ 1 + (secθ * cosec θ)
Read more about Trigonometric Identities at; brainly.com/question/7331447
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Answer: the answer is 1020
Step-by-step explanation: Because lets say 1032-133=899
so if we do 899+121=1020
Answer:
Experimental probability of head = 2 / 5 or 40%
Step-by-step explanation:
Given:
Total chances of getting head = 20 times
Number of heads come = 8
Find:
Experimental probability of head
Computation:
Experimental probability of head = Number of heads come / Total chances of getting head
Experimental probability of head = 8 / 20
Experimental probability of head = 2 / 5 or 40%
Answer:
753.98224 or 753.98
Step-by-step explanation:
V=π·6²·20/3=753.98224
