F ` ( x ) = ( x² )` · e^(5x) + x² · ( e^(5x) )` =
= 2 x · e^(5x) + 5 e^(5x) · x² =
= x e^(5x) ( 2 + 5 x )
f `` ( x ) = ( 2 x e^(5x) + 5 x² e^(5x) ) ` =
= ( 2 x ) ˙e^(5x) + 2 x ( e^(5x) )` + ( 5 x² ) ` · e^(5x) + ( e^(5x)) ` · 5 x² =
= 2 · e^(5x) + 10 x · e^(5x) + 10 x · e^(5x) + 25 x² · e^(5x) =
= e^(5x) · ( 2 + 20 x + 25 x² )
I got you !
Step-by-step explanation:
45 bulbs planted in first year.
65 bulbs the next year.
increase = 20 bulbs
Number of increase of planted tulip bulb is N = 65 - 45 = 20
( 20/45) x 100% = 44.4 % to the nearest tenths
Answer:
Yes.
Step-by-step explanation:
Yes, the given line can be used to make reasonable predictions of the number of cheese pizzas that will be sold, since the scatter points clearly show a trend.
As time goes on, the number of pizzas sold is getting bigger, and the trend is what created the line.
The data was taken over 8 consecutive weeks, so we can assume that it can be used in our prediction.
Since the trend has been pretty consistent over periods of time, we can expect it to continue in the upcoming weeks.
Answer:
Step-by-step explanation:
as you can see something amazing happens in 10 in this function . If you replace x with 10 you get 1/0 wich an indetermined form in Mathematics.
Now we are sure that there is a vertical asymptote in 10. Let's see identify the limit in the left of 10.
let's assign some values to x that are smaller than 10.
1. x=9
1/(9-10)= -1
a negative value
2. x=8
1/(8-10)= -1/2
a negative value
let try a reallu colse value to 10 like 9.99
1/(9.99-10)=-100
a negative value
so we can deduce that the limit is -∞
lim [1/(x-10)]=-∞
x→10-
Answer:-21.5
Step-by-step explanation:
It’s the furthest
