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Sever21 [200]
3 years ago
7

Help help help help help ASAP help hellppp​

Mathematics
1 answer:
JulijaS [17]3 years ago
8 0

Answer:

£280

Step-by-step explanation:

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Select all of the right triangles.
Mariulka [41]

Answer:

Step-by-step explanation:

Triangle ABC: 30^2 + 40^2 = 50^2 is a true statement, so by the Pythagorean theorem, this is a right triangle.

Triangle XYZ: 1^2 + 1^2 = 2^2 is a false statement, so by the Pythagorean theorem, this is not a right triangle.

Triangle EFG: 8^2 + 15^2 = 17^2 is a true statement, so by the Pythagorean theorem, this is a right triangle.

3 0
2 years ago
What is the axis of symmetry for the function y=-(x - 3)2 + 5?
PolarNik [594]
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11/2 = 5 1/2 x= 5.5
7 0
3 years ago
On the coordinate plane, what quadrant is the point (1 , 4) located in?
Gemiola [76]

Answer:

on the second one

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
The output value of a function is represented by P(200). What is the input value for this function?
denis23 [38]
Output = P(200)

Input value = 200
3 0
4 years ago
For the equation x2 = a, describe the values of a that will result in two real solutions, one real solution, and no real solutio
Tasya [4]
The equation given is x^{2} =a where a is some number.
We can solve for x by taking the square root of both sides.

x=plusminus \sqrt{a}

Now let's think through what happens for various values of a.

TWO SOLUTIONS
If a is a positive number the above yields two solutions. Take for example:
x^{2} =49
 \sqrt{49}=7 or -7
There will be two solutions (one positive and one negative) as there are two numbers (here -7 and +7) that when multiplied by themselves give 49. That is, 7^{2} =49 and (-7)^{2}=49. The positive root is called the principal root and the negative root is called the secondary root. This will be the case anytime we take the root of a positive number.

ONE SOLUTION
If a = 0 there is only one solution. That is because x^{2} =0 and x= \sqrt{0}. Zero is neither positive nor negative and it has only one root which is 0 itself. So in this case there is only one solution and it is 0.

NO (REAL) SOLUTIONS
If a is negative we would be taking the square root of a negative number. There is no (real) number that when multiplied by itself gives a negative number. Take for example x^{2} =-49 which gives us x= \sqrt{-49}. The square root of -49 is not 7 because (7)(7)=49 which is positive. The square root of -49 is not -7 because (-7)(-7)=49 which is also positive. There is no real number that gives -49 when multiplied by itself. I say "real" numbers because there do exist imaginary/complex numbers but because of the way the questions was asked I imagine you may not know about these yet.
7 0
4 years ago
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