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sashaice [31]
3 years ago
15

Which type of rigid transformation is shown?

Mathematics
1 answer:
drek231 [11]3 years ago
3 0

Answer:

we need more info

Step-by-step explanation:

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Lauren wants to save $300,000 to buy a restaurant 10 years from now. How much should she deposit
UNO [17]

Answer: $6444.14 would be deposited quarterly

Step-by-step explanation:

We would apply the formula for determining future value involving deposits at constant intervals. It is expressed as

S = R[{(1 + r)^n - 1)}/r][1 + r]

Where

S represents the future value of the investment.

R represents the regular payments made(could be weekly, monthly)

r = represents interest rate/number of interval payments.

n represents the total number of payments made.

From the information given,

S = $300000

r = 0.08/3 = 0.027

n = 3 × 10 = 30

Therefore,

300000 = R[{(1 + 0.027)^30 - 1)}/0.027][1 + 0.027]

300000 = R[{(1.027)^30 - 1)}/0.027][1.027]

300000 = R[{(2.224 - 1)}/0.027][1.027]

300000 = R[{(1.224)}/0.027][1.027]

300000 = R[45.33][1.027]

300000 = 46.55391R

R = 300000/46.55391

R = 6444.14

4 0
3 years ago
A. The actual building height will be 596 ft tall. You want your model to be 3 ft tall. What will the scale factor be? For this
astra-53 [7]

Answer: the answer is c

Step-by-step explanation:

If not i'm sorry have a good day/night

5 0
2 years ago
6) When a proportional relationship is graphed on a coordinate plane, it
cupoosta [38]

Answer:

5

Step-by-step explanation:

8 0
3 years ago
Factorise: a squared -9a + 20? What are all the steps?
Komok [63]
<span><span>First, factorise the quadratic equation a^2 - 9a+ 20</span><span>Find two numbers which add up to 9 and multiply to give 20. These numbers are 4 and 5.(a - 4) (a - 5)</span><span>
Does that make sense?</span></span>
4 0
3 years ago
Read 2 more answers
What is the equation of a parabola y(x) that has a vertex at point (− 1/3 , 0.3) and passes through point (− 2/15 , − 1/2 ).
Savatey [412]

bearing in mind that 0.3 = 3/10


\bf ~\hfill \textit{parabola vertex form}~\hfill \\\\ \begin{array}{llll} y=a(x- h)^2+ k\qquad \leftarrow \textit{we'll use this one}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{-\frac{1}{3}}{ h},\stackrel{\frac{3}{10}}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ y=a\left[ x-\left( -\cfrac{1}{3} \right) \right]^2+\cfrac{3}{10}\implies y=a\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}


\bf \textit{we also know a point } \begin{cases} x=-\frac{2}{15}\\\\ y=-\frac{1}{2} \end{cases}\implies -\cfrac{1}{2}=a\left( -\cfrac{2}{15}+\cfrac{1}{3} \right)^2+\cfrac{3}{10} \\\\\\ -\cfrac{1}{2}-\cfrac{3}{10}=a\left( \cfrac{1}{5} \right)^2\implies -\cfrac{4}{5}=a\left(\cfrac{1}{25} \right)\implies -\cfrac{4}{5}=\cfrac{a}{25}\implies \cfrac{-4\cdot 25}{5}=a \\\\\\ -4\cdot 5=a\implies \boxed{-20=a} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ ~\hfill y=-20\left( x+\cfrac{1}{3} \right)^2+\cfrac{3}{10}~\hfill

8 0
3 years ago
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