<span>x in (-oo:+oo)
(x+20)/2 = 3*x // - 3*x
(x+20)/2-(3*x) = 0
(x+20)/2-3*x = 0
(x+20)/2+(-3*2*x)/2 = 0
x-3*2*x+20 = 0
20-5*x = 0
(20-5*x)/2 = 0
(20-5*x)/2 = 0 // * 2
20-5*x = 0
20-5*x = 0 // - 20
-5*x = -20 // : -5
x = -20/(-5)
x = 4 so x= 4</span>
Answer:
a) (g(x), f(u)) = ( 7*√x , e^u )
b) y ' = 3.5 * e^(7*√x) / √x
Step-by-step explanation:
Given:
- The given function:
y = e^(7*√x)
Find:
- Express the given function as a composite of f(g(x)). Where, u = g(x) and y = f(u).
- Express the derivative of y, y'?
Solution:
- We will assume the exponent of the natural log to be the u. So u is:
u = g(x) = 7*√x
- Then y is a function of u as follows:
y = f(u) = e^u
- The composite function is as follows:
(g(x), f(u)) = ( 7*√x , e^u )
- The derivative of y is such that:
y = f(g(x))
y' = f' (g(x) ) * g'(x)
y' = f'(u) * g'(x)
y' = e^u* 3.5 / √x
- Hence,
y ' = 3.5 * e^(7*√x) / √x
Answer:
570 miles
Step-by-step explanation:
If Damian rides 38 each week and we want to know how much it was for 15 weeks, then we just multiply the two to get 570 miles in a 15 week period.
Answer:
8
Step-by-step explanation:
(-4) (2) (-1)
(-8) (-1)
(8)
<span>EF = BC = a
ÐF is a right angle.
FD = CA = b
triangle
EF = BC = a
angle F is a right angle.
FD = CA = b
In triangle DEF,
By Pythagoras Theorem,
a2 + b2 = c2
the given
AB=c= a^2 + b^2 square root
Theorefore AB = DE
But by construction, BC = EF
and CA = FD
triangle ABC congruent to DEF (S.S.S)
hope it helps
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