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Kay [80]
3 years ago
11

You have 2 boxes of 21 parts. On average, each individual work operation takes 3 minutes per part. At the end, packaging the ent

ire box as required takes 10 minutes. About how long should it take you to get all of the work done? *
Mathematics
1 answer:
kenny6666 [7]3 years ago
6 0

Answer:

2 hours, 26 minutes

Step-by-step explanation:

2 boxes of 21 parts = 42 total parts

3 minutes per part = 42 x 3 = 126 minutes

10 minutes per box to package = 10 x 2 = 20 minutes

126 + 20 = 146 minutes

2 hours = 120 minutes

146 - 120 = 26

Final Answer: 2 hours, 26 minutes

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Can you send a picture, because this doesn’t make it clear what the options are/what to do
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2 years ago
Help !!!!!!!!!!! me part 2 question read 1 then read 2 I andswer one need help with 2
sergiy2304 [10]

Answer:

The volume of a cylinder is given by πr²h where, r is the radius of the cylinder and h is the height of the cylinder. Also r=d/2 , where d is the diameter of the cylinder. Therefore the volume becomes one-fourth of the initial volume. ... The new volume is 730 mL.

7 0
3 years ago
The town of Hayward (CA) has about 50,000 registered voters. A political research firm takes a simple random sample of 500 of th
timama [110]

Answer: (0.076, 0.140)

Step-by-step explanation:

Confidence interval for population proportion (p) is given by :-

\hat{p}\pm z_{\alpha/2}\sqrt{\dfrac{\hat{p}(1-\hat{p})}{n}}

, where \hat{p} = sample proportion.

n= sample size.

\alpha = significance level .

z_{\alpha/2} = critical z-value (Two tailed)

As per given , we have

sample size : n= 500

The number of Independents.:  x= 54

Sample proportion of Independents\hat{p}=\dfrac{x}{n}=\dfrac{54}{500}=0.108

Significance level 98% confidence level : \alpha=1-0.98=0.02

By using z-table , Critical value : z_{\alpha/2}=z_{0.01}=2.33

The 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters will be :-

0.108\pm (2.33)\sqrt{\dfrac{0.108(1-0.108)}{500}}\\\\=0.108\pm2.33\times0.013880634\\\\=0.108\pm0.03234187722\\\\\approx0.108\pm0.032=(0.108-0.032,\ 0.108+0.032)=(0.076,\ 0.140)

Hence, the 98% confidence interval for the true percentage of Independents among Haywards 50,000 registered voters.= (0.076, 0.140)

8 0
3 years ago
A study investigated about 3000 meals ordered from Chipotle restaurants using the online site Grubhub. Researchers calculated th
Allisa [31]

Answer:

21.186%

Step-by-step explanation:

z = (x-μ)/σ,

where

x is the raw score = 2400mg

μ is the population mean = 2000mg

σ is the population standard deviation = 500mg

z = 2400 - 2000/500

z = 0.8

Probability value from Z-Table:

P(x<2400) = 0.78814

P(x>2400) = 1 - P(x<2400) = 0.21186

Converting to percentage:

0.21186 × 100

= 21.186%

Therefore, the percent of the meals

ordered that exceeded the recommended daily allowance of 2400 mg of sodium is 21.186%

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3 years ago
What must be a factor of the polynomial function f(x) graphed on the coordinate plane below?
Nady [450]
The correct answer is x because u have to look on the x axis
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