All categories

3 years ago

I'm not sure how to do this

Mathematics

1 answer:

VMariaS [17]3 years ago

3 0

Answer:

1 and 5 sevenths of a bag

Step-by-step explanation:

2/7 males half to it takes 4/7 to make a full one multiply 4 by 3 and you get 12/7 so that makes 1 and 5/7

You might be interested in

Helpppppppppppppooppppppppoopppppppppppppp

MrRissso [65]

I need points soo I can post my question an get help my self...

3 0

3 years ago

Read 2 more answers

Dy/dx = 2xy^2 and y(-1) = 2 find y(2)

Anarel [89]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2887301

—————

Solve the initial value problem:

dy
——— = 2xy², y = 2, when x = – 1.
dx

Separate the variables in the equation above:

$\mathsf{\dfrac{dy}{y^2}=2x\,dx}\\\\
\mathsf{y^{-2}\,dy=2x\,dx}$

Integrate both sides:

$\mathsf{\displaystyle\int\!y^{-2}\,dy=\int\!2x\,dx}\\\\\\
\mathsf{\dfrac{y^{-2+1}}{-2+1}=2\cdot \dfrac{x^{1+1}}{1+1}+C_1}\\\\\\
\mathsf{\dfrac{y^{-1}}{-1}=\diagup\hspace{-7}2\cdot \dfrac{x^2}{\diagup\hspace{-7}2}+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{y}=x^2+C_1}$

$\mathsf{\dfrac{1}{y}=-(x^2+C_1)}$

Take the reciprocal of both sides, and then you have

$\mathsf{y=-\,\dfrac{1}{x^2+C_1}\qquad\qquad where~C_1~is~a~constant\qquad (i)}$

In order to find the value of C₁ , just plug in the equation above those known values for x and y, then solve it for C₁:

y = 2, when x = – 1. So,

$\mathsf{2=-\,\dfrac{1}{1^2+C_1}}\\\\\\
\mathsf{2=-\,\dfrac{1}{1+C_1}}\\\\\\
\mathsf{-\,\dfrac{1}{2}=1+C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-1=C_1}\\\\\\
\mathsf{-\,\dfrac{1}{2}-\dfrac{2}{2}=C_1}$

$\mathsf{C_1=-\,\dfrac{3}{2}}$

Substitute that for C₁ into (i), and you have

$\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}}\\\\\\
\mathsf{y=-\,\dfrac{1}{x^2-\frac{3}{2}}\cdot \dfrac{2}{2}}\\\\\\
\mathsf{y=-\,\dfrac{2}{2x^2-3}}$

So y(– 2) is

$\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot (-2)^2-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{2\cdot 4-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{8-3}}\\\\\\
\mathsf{y\big|_{x=-2}=-\,\dfrac{2}{5}}\quad\longleftarrow\quad\textsf{this is the answer.}$

I hope this helps. =)

Tags: <em>ordinary differential equation ode integration separable variables initial value problem differential integral calculus</em>

7 0

3 years ago

Describe several real world situations can be modeled by equations of the form Y equals MX plus be or Y equals MX explain how th

lara [203]

The linear equation represents y = mx + b describes several real world situations such as

Relation between printer and ink cartridges,

Relationship between number of songs and how much is left on the card.

<u>Step-by-step explanation</u>:

Linear equations y = mx + b.

m is your rate of change.

b is your constant. This is the initial value of y. The value of y when x is 0.

Finally, y is the thing that depends on x.

Oh right, examples:

I buy a printer for $100 and the ink cartridges cost $25 each. The relationship between ink cartridges and total cost.

total cost = 25(cartridges I buy) + 100 or y = 25x + 100

I get a $100 iTunes gift card for my birthday and then start buying $1 songs. The relationship between the number of songs I buy and how much is left on the card

amount left on card = -$1(songs bought) + 100 or y = -x +100

5 0

2 years ago

In the problem 10 take away 4 equals 6 what is the correct term for the number 4

crimeas [40]

10 would be called the Minuend.
4 would be called the Subtrahend.
4 would be the Difference.

5 0

3 years ago

Read 2 more answers

HELP PLEASE

Alex787 [66]

The answer that i got for your question is the first answer.