Question

TS is the height of a building. PQR is a pole in front of the building. QT is a horizontal cable that supports the pole to the building. Find the height of the pole?​

Answer 1

Answer:

The answer is 65.75

Step-by-step explanation:

Since tq is perpendicular to PR then qtsr becomes square

Then

$qr = 30 \: \: \: \: \: and \: qt = 30$

Since the triangle pqt is right angled

Then

$pq = qt \tan(50) = 30 \times \tan(50 ) = 35.75$

Then the height of the pole is equal to

$pq + qr = 35.75 + 30 = 65.75$