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2 years ago

7

PLS HELP ME FIND THE MAD, MADIAN, RANGE AND IQR OF THIS DATA SET.

2 answers:

sweet-ann [11.9K]2 years ago

8 0

Answer:

The median is 6. The Mean Absolute Deviation is 1.88. The range is 10. I believe the IQR is 5.

Step-by-step explanation:

the median is just the number that falls in the center of a data set. The Mean Absolute Deviation is the distance of the data points from the mean. So, find the sum of the differences of each data point from the mean and divide it by the number of data points. Range is the difference between the smallest and largest values in a data set. The interquartile range is the middle of the data. it is a measure of how widely the middle half of the data is spread around the median.

My name is Ann [436]2 years ago

4 0

Answer:

the median is 6, range is 10, the iqr is 6 and the MAD is 1.9378698224852

Step-by-step explanation:

Range

10 - 0 = 10

IQR

median/2

6/2=3

6+3=9 6-3=3

9-3=6

Median

put numbers in ascending order

04445555555566678888899101010

find centre number

6

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Step-by-step explanation:

3.3+5(-7 + 4)

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3 years ago

Read 2 more answers

n 2018, homes in East Baton Rouge (EBR) Parish sold for an average of $239,000. You take a random sample of homes in Ascension p

Olenka [21]

Answer:

Conclusion

There is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

Step-by-step explanation:

From the question we are told that

The population mean for EBR is $\mu_ 1 = \$239,000$

The sample mean for Ascension parish is $\= x_2 = \$246,000$

The p-value is $p-value = 0.045$

The level of significance is $\alpha = 0.01$

The null hypothesis is $H_o : \mu_2 = \mu_1$

The alternative hypothesis is $H_a : \mu_2 > \mu_1$

Here $\mu_2$ is the population mean for Ascension parish

From the data given values we see that

$p-value > \alpha$

So we fail to reject the null hypothesis

So we conclude that there is no sufficient evidence to conclude that the mean of the home prices from Ascension parish is higher than the EBR mean

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